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Question

Find the value of $7500 + (1250 \div 50)$.

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
7525

Solving the Arithmetic Expression: $7500 + (1250 \div 50)$

Problem Analysis

The question requires finding the value of the expression $7500 + (1250 \div 50)$. This involves two operations: division and addition. According to the order of operations (BODMAS/PEMDAS), division must be performed before addition.

Step-by-Step Solution

  • Step 1: Perform the division

    Calculate the value inside the parentheses first: $1250 \div 50$.

    $1250 \div 50 = 25$

  • Step 2: Perform the addition

    Add the result from Step 1 to $7500$.

    $7500 + 25 = 7525$

Result

The value of the expression $7500 + (1250 \div 50)$ is $7525$. This corresponds to Option D.

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Important Questions from Bodmas Rule

  1. The value of 90 ÷ 20 of 6 × [11 ÷ 4 of {3 × 2 - (3 - 8)}] ÷ (9 ÷ 3 × 2) is:

  2. The value of 1800 ÷ 20 × {(12 - 6) + (24 - 12)} is:

  3. The value of 20 ÷ 5 of 8 × [9 ÷ 6 × (6 - 3)] - (10 ÷ 2 of 20) is:

  4. The value of \(\left( {18 \div 2\;of\frac{1}{4}} \right)\; \times \;\left( {\frac{2}{3} \div \frac{3}{4}\; \times \;\frac{5}{8}} \right) \div \left( {\frac{2}{3} \div \frac{3}{4}of\frac{3}{4}} \right)\) is:

  5. The value of 18 ÷ [26 - {25 - (15 - 5) ÷ 2}] of 12 + 2 - 2 ÷ 4 × 16 is:

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