Find the number of trailing zeros in 76!.
18
Trailing zeros in n! equal the number of factors of 5 in n!, found by adding the integer parts of n/5, n/25, n/125 and so on.
For 76!: [76/5] = 15 and [76/25] = 3, while [76/125] = 0.
Number of trailing zeros = 15 + 3 = 18.
Hence, 18.
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Important Questions from Multiples and Factors
Express 486 as a product of powers of prime factors.
Let p, q, r and s be positive natural numbers having three exact factors including 1 and the number itself. If q > p and both are two-digit numbers, and r > s and both are one-digit numbers, then the value of the expression \(\frac{p-q-1}{r-s}\) is:
Find the greatest three-digit number which is a multiple of 8.
The sum of three consecutive multiples of 7 is 840. The smallest of these multiples is:
If 2160 = 2 a × 3 b × 5 c , then the value of 3 a × 2 -b × 5 -c will be –
