Find the number of trailing zeros in 124!.
28
Each trailing zero comes from a factor 10 = 2 × 5, and factors of 5 are fewer than factors of 2 in a factorial.
Number of 5s in 124! = [124/5] + [124/25] + [124/125] = 24 + 4 + 0.
So 124! has 24 + 4 = 28 trailing zeros.
Hence, 28.
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