Find the minimum value of \(x\) which makes \(\frac{136}{x-4}\) an integer.
-132
\(-132\) is correct.
The fraction \(\dfrac{136}{x-4}\) is an integer only when \(x-4\) is a divisor of 136, positive or negative.
The smallest possible divisor of 136 is \(-136\), so the smallest \(x\) comes from \(x - 4 = -136\).
Then \(x = -136 + 4 = -132\), and \(\dfrac{136}{-136} = -1\) is an integer.
For \(x = -268\), \(x - 4 = -272\) and \(\dfrac{136}{-272} = -0.5\), which is not an integer.
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select the correct answer using the code given below:
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