Find the median of the following data (correct to two places of decimal).Class interval 0-6 6-12 12-18 18-24 24-30 30-36 Frequency 5 7 10 13 9 8
19.85
First find the total frequency: \(N = 5 + 7 + 10 + 13 + 9 + 8 = 52\).
So \(\frac{N}{2} = \frac{52}{2} = 26\).
The cumulative frequencies are 5, 12, 22, 35, 44, 52. The value 26 first exceeds 22 in the class 18-24, so this is the median class.
Here \(L = 18\), cumulative frequency before the class \(cf = 22\), frequency \(f = 13\) and class width \(h = 6\).
Median \(= L + \frac{\frac{N}{2} - cf}{f} \times h = 18 + \frac{26 - 22}{13} \times 6 = 18 + \frac{4}{13} \times 6\).
\(= 18 + 1.846 = 19.85\) (to two decimals).
Hence, the median of the data is 19.85.
| Height (cm) | Number of persons |
|---|---|
| 120 | 3 |
| 130 | 4 |
| 140 | 5 |
| 150 | 6 |
| 160 | 2 |
| Value | 3 | 2 | k | 4 | 5 |
| Frequency | k | 2k | 3k | 4k | 5k |
In a colony 5 families have 1 child, 7 families have 2 children, 8 families have 3 children and 3 families have 4 children.What is the mode of the number of children.
What will be the difference between mean and median of the given data?
21, 11, 27, 8, 5, 12, 7, 23, 3, 14, 9, 19Find the mode and median of 3, 4, 5, 5, 3, 6, 7, 3, 5, 5, 6.
A. 5 and 5
B. 3 and 5
C. 5 and 4
D. 3 and 4
For which set of numbers do the mean, median and mode all have the same value?
The median of 5, 8, 25, 22, 34, 18 is