Find the diameter of a sphere of surface area 28962 cm2. (round off to the closest integer) (Take $\pi$ = $\frac{22}{7}$)
96 cm
The surface area of a sphere of radius \(r\) is \(S = 4\pi r^2\).
Substitute \(S = 28962\) cm2: \(4\pi r^2 = 28962\).
Solve for \(r^2\): \(r^2 = \frac{28962}{4\pi} = \frac{28962}{12.566} \approx 2304.9\).
Take the square root: \(r = \sqrt{2304.9} \approx 48.01\) cm.
The diameter is twice the radius: \(d = 2r \approx 2 \times 48.01 = 96.02\) cm.
Rounded to the closest integer, the diameter is 96 cm.
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Important Questions from 3-D Mensuration
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
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(Use $\pi = \frac{22}{7}$)- A cylindrical rod has an curved surface area of $4,900 \text{ cm}^2$. If the length of the rod is 97 cm, then the radius (in cm) of the rod, correct to two places of decimal, is:
Take $\pi = \frac{22}{7}$ - The volume (in $m^3$) of a cube, each of whose edges is 42 m, is:
