Find mass (in gm) of a gold coin of radius 2 cm and thickness 0.05 cm. (Density of gold 19.3 gm/cm 3)
12.1
This question asks us to find the mass of a gold coin given its physical dimensions (radius and thickness) and the density of gold. To solve this, we need to first calculate the volume of the coin and then use the relationship between mass, density, and volume.
A gold coin is typically shaped like a cylinder. We are given the following information:
We need to find the mass of the gold coin.
The volume of a cylinder is calculated using the formula:
$V = \pi r^2 h$
Where:
Let's plug in the given values for the gold coin:
$V = \pi \times (2 \text{ cm})^2 \times 0.05 \text{ cm}$
$V = \pi \times 4 \text{ cm}^2 \times 0.05 \text{ cm}$
$V = (4 \times 0.05) \pi \text{ cm}^3$
$V = 0.2 \pi \text{ cm}^3$
Using the approximate value of $\pi \approx 3.14159$, the volume is:
$V \approx 0.2 \times 3.14159 \text{ cm}^3$
$V \approx 0.628318 \text{ cm}^3$
The relationship between mass, density, and volume is given by the formula:
$\text{Mass} = \text{Density} \times \text{Volume}$
We have the density of gold and the calculated volume of the gold coin. Now, we can find the mass:
$\text{Mass} = 19.3 \text{ gm/cm}^3 \times 0.628318 \text{ cm}^3$
$\text{Mass} \approx 12.13753 \text{ gm}$
Let's look at the given options for the mass of the gold coin:
Our calculated mass, approximately 12.13753 gm, is very close to 12.1 gm.
Based on the calculations using the dimensions and density of the gold coin, the mass is approximately 12.1 gm.
| Property | Value | Units |
|---|---|---|
| Radius (r) | 2 | cm |
| Thickness (h) | 0.05 | cm |
| Density ($\rho$) | 19.3 | gm/cm$^3$ |
| Calculated Volume (V) | 0.2$\pi$ \(\approx 0.628\) | cm$^3$ |
| Calculated Mass | 19.3 \(\times\) 0.2$\pi$ \(\approx 12.138\) | gm |
| Concept | Formula Used | Inputs | Output |
|---|---|---|---|
| Volume of Cylinder | $V = \pi r^2 h$ | $r=2$ cm, $h=0.05$ cm | $V = 0.2\pi$ cm$^3$ |
| Mass from Density | Mass = $\rho \times V$ | $\rho=19.3$ gm/cm$^3$, $V=0.2\pi$ cm$^3$ | Mass = $19.3 \times 0.2\pi \approx 12.138$ gm |
Density: Density is a fundamental physical property of a substance that describes how much mass is contained in a given volume. It is defined as mass per unit volume. The formula is $\rho = \text{Mass} / \text{Volume}$. Different materials have different densities. For example, gold is much denser than water or aluminum.
Volume: Volume is the amount of three-dimensional space occupied by an object. The formula for volume depends on the shape of the object. For simple shapes like cylinders, spheres, and cubes, there are standard formulas. For irregular shapes, volume can be measured using methods like displacement.
In this problem, understanding that a coin is a cylinder and knowing the formula for the volume of a cylinder were key steps. We then applied the definition of density to find the mass.
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