What is the binary equivalent of decimal 413?
110011101
Converting a number from the decimal system (base 10) to the binary system (base 2) is a fundamental concept in computer science and digital electronics. The decimal system uses ten digits (0-9), while the binary system uses only two digits (0 and 1).
To convert a decimal number to its binary equivalent, we typically use the method of repeated division by 2. In this method, the decimal number is repeatedly divided by 2, and the remainders are recorded at each step. The binary equivalent is then obtained by reading the remainders from bottom to top.
Let's apply the repeated division by 2 method to convert the decimal number 413 into its binary form.
We divide 413 by 2 and record the quotient and the remainder. We continue this process with the quotient until the quotient becomes 0.
| Division | Quotient | Remainder |
|---|---|---|
| \(413 \div 2\) | 206 | 1 |
| \(206 \div 2\) | 103 | 0 |
| \(103 \div 2\) | 51 | 1 |
| \(51 \div 2\) | 25 | 1 |
| \(25 \div 2\) | 12 | 1 |
| \(12 \div 2\) | 6 | 0 |
| \(6 \div 2\) | 3 | 0 |
| \(3 \div 2\) | 1 | 1 |
| \(1 \div 2\) | 0 | 1 |
Now, we read the remainders from the bottom upwards:
The remainders, in order from bottom to top, are 1, 1, 0, 0, 1, 1, 1, 0, 1.
Therefore, the binary equivalent of decimal 413 is 110011101.
We can verify this binary number by converting it back to decimal. Each digit in a binary number represents a power of 2, starting from \(2^0\) on the rightmost side.
The binary number is \(110011101_2\). Let's convert it to decimal:
\(1 \times 2^8 + 1 \times 2^7 + 0 \times 2^6 + 0 \times 2^5 + 1 \times 2^4 + 1 \times 2^3 + 1 \times 2^2 + 0 \times 2^1 + 1 \times 2^0\)
\(= 1 \times 256 + 1 \times 128 + 0 \times 64 + 0 \times 32 + 1 \times 16 + 1 \times 8 + 1 \times 4 + 0 \times 2 + 1 \times 1\)
\(= 256 + 128 + 0 + 0 + 16 + 8 + 4 + 0 + 1\)
\(= 413\)
The calculation confirms that the binary 110011101 is indeed equivalent to decimal 413.
| System | Base | Digits Used | Example (Base 10 Value) |
|---|---|---|---|
| Decimal | 10 | 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 | \(413_{10}\) |
| Binary | 2 | 0, 1 | \(110011101_2\) (\(413_{10}\)) |
| Octal | 8 | 0, 1, 2, 3, 4, 5, 6, 7 | \(635_8\) (\(413_{10}\)) |
| Hexadecimal | 16 | 0-9, A-F | \(19D_{16}\) (\(413_{10}\)) |
The binary system is crucial in digital circuits and computers because they operate using two voltage levels, which can represent 0 and 1. Understanding binary conversion is essential for working with computer memory, data representation, and low-level programming.
Other methods exist for decimal to binary conversion, such as the sum of powers of 2 method, but repeated division is generally the most straightforward for converting integers.
When dealing with fractional decimal numbers, the fractional part is converted to binary by repeated multiplication by 2, recording the integer part at each step.
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