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Question

Fifteen houses are located in a row such that the distance between two adjacent houses is equal. If the distance between the $1^{\text{st}}$ and $15^{\text{th}}$ house is 560 ft., then what is the distance between the $3^{\text{rd}}$ and $7^{\text{th}}$ house?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
160 ft.

Understanding House Intervals

The problem involves houses arranged in a row with equal spacing. The key is to determine the number of intervals between the houses, not just the number of houses.

  • Total number of houses = 15.
  • The number of equal intervals between 15 houses is \(15 - 1 = 14\).

Calculating Distance Per Interval

The total distance between the $1^{\text{st}}$ and $15^{\text{th}}$ house is given as 560 ft. This distance covers the 14 intervals.

Distance per interval = $ \frac{\text{Total Distance}}{\text{Number of Intervals}} $

Distance per interval = $ \frac{560 \text{ ft}}{14} = 40 \text{ ft} $.

Determining Distance Between 3rd and 7th House

We need to find the distance between the $3^{\text{rd}}$ and $7^{\text{th}}$ house. This involves houses from the $3^{\text{rd}}$ up to the $7^{\text{th}}$.

  • The number of houses involved in this segment is $7 - 3 = 4$.
  • The number of intervals between the $3^{\text{rd}}$ and $7^{\text{th}}$ house is $7 - 3 = 4$.

Distance = Number of intervals $\times$ Distance per interval

Distance = $4 \times 40 \text{ ft} = 160 \text{ ft}$.

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