Evaluate \(22^3 + (-18)^3 + (-4)^3\).
4752
Let \(a = 22\), \(b = -18\), \(c = -4\). Since \(a + b + c = 22 - 18 - 4 = 0\), the identity \(a^3 + b^3 + c^3 = 3abc\) applies.
So \(a^3 + b^3 + c^3 = 3 \times 22 \times (-18) \times (-4) = 3 \times 1584 = 4752\).
Hence, the value of the expression is 4752.
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