Question
Evaluate \(22^3 + (-16)^3 + (-6)^3\)
This question was previously asked in
RRB NTPC 2025 Graduate CBT 2 Question Paper PDF (10-Jul-2026) (Shift 1)
The correct answer is
6336
\(22^3 = 10648\), \((-16)^3 = -4096\), \((-6)^3 = -216\).
Sum: \(10648-4096-216 = 6336\).
Hence, the value of the expression is 6336.
Was this answer helpful?
Similar Questions
- Find the least number by which 6250 should be multiplied, so that it becomes a perfect cube.
- Find the smallest natural number N such that the product $288 \times N$ is a perfect cube.
- The square root of 18769 consists of how many digits?
- The square root of $1\frac{11}{25}$ is:
- The value of $\sqrt{142884}$ is:
- The number by which 62557 can be divided to make it a perfect cube is:
- What is the value of $101^3$?
- What is the value of $99^3$?
- The value of $\sqrt[5]{\frac{32}{243}}$ is ________.
- The cube root of 250 lies between:
Important Questions from Cube and Cube Root
Find the value of (25)3 + (-29)3 + (4)3
The value of \(\frac{\sqrt[3]{-2744} \times \sqrt[3]{-216}}{\sqrt[3]{\frac{64}{729}}}\) is:
The sum of a positive number and its cube is 1740. What is the value of the number?
The largest four digit number which is a perfect cube is:
What is the cube root of 1728?
Need Expert Advice?
Upcoming Exams
RRB NTPC
September 27, 2026
Test Series
Railways
RRB NTPC Under Graduate 2026 New Mock Test Series
1580 Tests 2 Tests Free
381 Attempts
4.3(493)
English, Hindi, Telugu +7 More
More Questions from RRB NTPC
