As per Indian Railways standards, what is the degree of curvature for a railway curve with a radius of 875 m?
2°
To determine the degree of curvature for a railway curve, we need to understand what the degree of curvature represents. The degree of curvature in railway engineering is defined as the angle subtended at the center of a circular curve by a 30-meter arc. This relationship is essential for computing the degree of curvature when the radius is known.
The formula to calculate the degree of curvature (D) is:
D = \frac{360}{2\pi R}\times \text{arc length}
In railway standards, the arc length is typically set at 30 meters. Therefore, the formula becomes:
D = \frac{360}{2\pi R} \times 30
Given:
- Radius, R = 875 \, \text{m}
Substituting these values into the formula, we get:
D = \frac{360 \times 30}{2\pi \times 875}
Calculate the degree of curvature:
D = \frac{10800}{2\pi \times 875}
D = \frac{10800}{5495.54}
D \approx 1.965 \approx 2^\circ
Therefore, the degree of curvature for a railway curve with a radius of 875 meters is approximately 2°.
Conclusion: The correct answer is 2^\circ, matching the given correct answer option.
Important Questions from Curves
The radius of a simple circular curve is 300m and the length of its specified chord is 20 m, The degree of the curve is:
Which of the following methods is NOT commonly used in setting out circular curves?
A curve which consists of two circular arcs of same and different radii having their centres to the different sides of the common tangent is called:
The tangent length for a simple curve is 10 m. the chainage of point of intersection is 344.465 m. The chainage of starting point of curve is:
In India, the standard chord length used in curves is:
