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Question

As per Indian Railways standards, what is the degree of curvature for a railway curve with a radius of 875 m?

This question was previously asked in
RRB JE 2025 CBT 2 Mechanical and Allied Engg Question Paper English (2-Jul-2026) (Shift-1)
The correct answer is

To determine the degree of curvature for a railway curve, we need to understand what the degree of curvature represents. The degree of curvature in railway engineering is defined as the angle subtended at the center of a circular curve by a 30-meter arc. This relationship is essential for computing the degree of curvature when the radius is known.

The formula to calculate the degree of curvature (D) is:

D = \frac{360}{2\pi R}\times \text{arc length}

In railway standards, the arc length is typically set at 30 meters. Therefore, the formula becomes:

D = \frac{360}{2\pi R} \times 30

Given:

  • Radius, R = 875 \, \text{m}

Substituting these values into the formula, we get:

D = \frac{360 \times 30}{2\pi \times 875}

Calculate the degree of curvature:

D = \frac{10800}{2\pi \times 875}

D = \frac{10800}{5495.54}

D \approx 1.965 \approx 2^\circ

Therefore, the degree of curvature for a railway curve with a radius of 875 meters is approximately 2°.

Conclusion: The correct answer is 2^\circ, matching the given correct answer option.

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Important Questions from Curves

  1. The point where the alignment changes from a straight line or tangent to a circular curve is called as-

  2. Which of the following checks is applied to verify the accuracy of the setting of simple curves?

  3. Perpendicular offset from a tangent to the junction of a transition curve and circular curve is equal to _____

    Where ‘S’ is shift.
  4. The radius of a simple circular curve is 300m and the length of its specified chord is 20 m, The degree of the curve is:

  5. In a simple curve, external distance is the distance between:

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