Correct order of boiling points in the following is: (A) CH3CHO (B) CH3COOH (C) CH3CH2OH (D) CH3CH3 (E) CH3CH2Cl Choose the correct answer from the options given below:
(B), (C), (A), (E), (D)
The boiling point of a substance is the temperature at which its vapor pressure equals the surrounding atmospheric pressure, allowing it to change from a liquid to a gas. This process requires overcoming the attractive forces between molecules in the liquid state. These attractive forces are known as intermolecular forces. Stronger intermolecular forces require more energy to overcome, resulting in higher boiling points.
There are several types of intermolecular forces:
To determine the correct order of boiling points for the given compounds, we need to identify the primary intermolecular forces present in each and compare their relative strengths.
Let's examine the structure and polarity of each given compound:
(A) $\text{CH}_3\text{CHO}$ (Acetaldehyde): This is an aldehyde. The $\text{C}=\text{O}$ carbonyl group is polar due to the difference in electronegativity between carbon and oxygen. Acetaldehyde is a polar molecule and exhibits dipole-dipole forces in addition to London dispersion forces.
(B) $\text{CH}_3\text{COOH}$ (Acetic Acid): This is a carboxylic acid. It contains both a $\text{C}=\text{O}$ group and an $\text{-OH}$ group. The $\text{-OH}$ group allows for strong hydrogen bonding between molecules. Carboxylic acids often form dimers in which two molecules are held together by two hydrogen bonds, significantly increasing the effective molecular size and intermolecular attraction. It also exhibits dipole-dipole and London dispersion forces.
(C) $\text{CH}_3\text{CH}_2\text{OH}$ (Ethanol): This is an alcohol. It contains an $\text{-OH}$ group. The oxygen atom is highly electronegative and bonded to hydrogen, allowing for hydrogen bonding between molecules. It also exhibits dipole-dipole and London dispersion forces.
(D) $\text{CH}_3\text{CH}_3$ (Ethane): This is a simple alkane. It is a nonpolar molecule. The only intermolecular forces present are weak London dispersion forces.
(E) $\text{CH}_3\text{CH}_2\text{Cl}$ (Chloroethane): This is an alkyl halide. The $\text{C}-\text{Cl}$ bond is polar due to the electronegativity difference between carbon and chlorine. Chloroethane is a polar molecule and exhibits dipole-dipole forces in addition to London dispersion forces.
In general, the strength of intermolecular forces follows this order:
Hydrogen Bonding > Dipole-Dipole Forces > London Dispersion Forces
Let's rank the compounds based on the strongest intermolecular forces present:
Combining the rankings based on intermolecular forces:
Carboxylic Acid (Hydrogen bonding, dimerization) > Alcohol (Hydrogen bonding) > Aldehyde (Dipole-dipole) > Alkyl Halide (Dipole-dipole) > Alkane (London dispersion)
Therefore, the expected order of boiling points from highest to lowest is:
The correct order from highest to lowest boiling point is (B), (C), (A), (E), (D).
| Compound | Structure/Formula | Functional Group | Primary Intermolecular Forces | Relative Boiling Point |
|---|---|---|---|---|
| (A) Acetaldehyde | $\text{CH}_3\text{CHO}$ | Aldehyde | Dipole-Dipole, LDF | Intermediate |
| (B) Acetic Acid | $\text{CH}_3\text{COOH}$ | Carboxylic Acid | Hydrogen Bonding (strong), Dipole-Dipole, LDF | Highest |
| (C) Ethanol | $\text{CH}_3\text{CH}_2\text{OH}$ | Alcohol | Hydrogen Bonding, Dipole-Dipole, LDF | High |
| (D) Ethane | $\text{CH}_3\text{CH}_3$ | Alkane | LDF | Lowest |
| (E) Chloroethane | $\text{CH}_3\text{CH}_2\text{Cl}$ | Alkyl Halide | Dipole-Dipole, LDF | Lower Intermediate |
| Compound | Code | Functional Group | Key Intermolecular Force | Relative Boiling Point |
|---|---|---|---|---|
| Acetic Acid | (B) | Carboxylic Acid | Strong Hydrogen Bonding | Highest |
| Ethanol | (C) | Alcohol | Hydrogen Bonding | High |
| Acetaldehyde | (A) | Aldehyde | Dipole-Dipole | Intermediate |
| Chloroethane | (E) | Alkyl Halide | Dipole-Dipole | Lower Intermediate |
| Ethane | (D) | Alkane | London Dispersion | Lowest |
Intermolecular forces are crucial in determining various physical properties of substances, including boiling point, melting point, viscosity, and surface tension. Substances with stronger intermolecular forces generally have higher boiling points and melting points because more energy is required to overcome these attractions and change the state of matter.
When comparing molecules, it's important to consider both the types and strengths of intermolecular forces as well as molecular size (for LDF contribution). However, the presence of hydrogen bonding usually dominates over dipole-dipole and LDFs for molecules of similar size.
Which isomerism is shown by the following pairs?
CH₃CH₂CH₂OH and CH₃CH₂OCH₃
Identify allylic alcohol:
(A) CH2= CH–CH2OH
(B) CH3= CH–CH2OH
(C) 
(D) 
Choose the correct answer from the options given below:
In Kolbe's reaction, phenol undergoes:
Identify "A" and mention the name of the mechanism through which it is formed:
When methyl bromide is treated with sodium tert-butoxide, the compound formed is: