According to Carson’s Rule, the approximate bandwidth of a frequency modulation signal is __________.
Twice the sum of the frequency deviation and the highest modulating frequency
This question asks for the bandwidth of a frequency-modulation (FM) signal according to Carson's Rule. A key feature of FM is that it is theoretically an infinite-bandwidth signal — the modulation process generates an infinite number of sidebands spaced at multiples of the modulating frequency around the carrier. In practice, however, the amplitudes of sidebands far from the carrier become negligibly small, so an effective finite bandwidth is defined that contains essentially all the significant power.
Carson's Rule gives this practical estimate:
BT = 2(Δf + fm)
This means the bandwidth is twice the sum of the frequency deviation and the highest modulating frequency — the correct option. The rule captures approximately 98% of the total FM signal power within BT. An equivalent form is BT = 2fm(β + 1), where β = Δf / fm is the modulation index; substituting β back in reproduces the same expression.
Why the other options are wrong:
Which of the following is NOT the advantage of frequency modulation ?
Which of the following statements is true for FM?
The modulation technique in which frequency of the carrier wave is changed with respect to the modulating wave is called:
A phase locked loop can be used to demodulate
What is the modulation index in a frequency modulated signal with a modulating frequency of 500 Hz and frequency deviation of 10 kHz?