Before 4 years, the age of A was twice the age of B. After 6 years, the age of C will be twice the age of A. The current age of A is 10 years more than that of B. What is the current age of C?
54 years
This problem involves finding the current ages of three individuals, A, B, and C, based on relationships between their ages at different points in time. We are given three conditions that relate their ages.
Let's represent the current ages of A, B, and C with variables:
We can translate the given information into mathematical equations:
4 years ago, A's age was \(A - 4\). 4 years ago, B's age was \(B - 4\). The condition states \( (A - 4) = 2 \times (B - 4) \). This simplifies to: \(A - 4 = 2B - 8\) \(A = 2B - 8 + 4\) \(A = 2B - 4\) (Equation 1)
This directly translates to: \(A = B + 10\) (Equation 2)
After 6 years, C's age will be \(C + 6\). After 6 years, A's age will be \(A + 6\). The condition states \( (C + 6) = 2 \times (A + 6) \). This simplifies to: \(C + 6 = 2A + 12\) \(C = 2A + 12 - 6\) \(C = 2A + 6\) (Equation 3)
We now have a system of three equations with three variables. We can solve this system to find the current ages.
We have two equations relating A and B:
Since both equations are equal to A, we can set them equal to each other:
\(2B - 4 = B + 10\)
Now, solve for B:
\(2B - B = 10 + 4\)
\(B = 14\)
So, the current age of B is 14 years.
Now substitute the value of B into either Equation 1 or Equation 2 to find A. Using Equation 2 is simpler:
\(A = B + 10\)
\(A = 14 + 10\)
\(A = 24\)
So, the current age of A is 24 years.
Now that we know the current age of A (which is 24 years), we can use Equation 3 to find the current age of C:
Substitute the value of A into Equation 3:
\(C = 2 \times 24 + 6\)
\(C = 48 + 6\)
\(C = 54\)
So, the current age of C is 54 years.
Based on our calculations:
Let's quickly check if these ages satisfy the original conditions:
All conditions are satisfied, confirming our calculated ages are correct.
The current age of C is 54 years.
| Person | Age 4 Years Ago | Current Age | Age 6 Years From Now |
|---|---|---|---|
| A | \(A-4 = 20\) | \(A = 24\) | \(A+6 = 30\) |
| B | \(B-4 = 10\) | \(B = 14\) | \(B+6 = 20\) |
| C | \(C-4 = 50\) | \(C = 54\) | \(C+6 = 60\) |
Age problems are common in algebra and quantitative aptitude sections of exams. They typically involve relationships between current ages or ages at different points in time (past or future).
Practicing various types of age problems helps in quickly setting up the correct equations and solving them efficiently.
₹5,110 is to be divided among Rajesh, Vivek and Kripal in such a way that Rajesh gets double the amount that Vivek gets, and Kripal gets double the amount that Rajesh gets. How much money will Kripal get?
If the sum of a number, its square and its cube is 584, then what is the number?
Among five pencils, A, B, C, D and E, the length of D is 10 cm. A is half the length of D but double the length of C. E is 2 cm longer than C. The length of B is equal to the lengths of A and E taken together. Which is the longest pencil?
The sum of the scores obtained by Ram and his two friends in an exam is 60% of the sum of the maximum marks for the exam for all three of them. If the ratio of their obtained marks is 4 ∶ 5 ∶ 6, how many of them scored more than 70% marks in the exam?
When the petrol prices increased by 25%, Yogesh reduced his travel so as to keep his monthly expenses on petrol the same as earlier. By what percentage did Yogesh reduce his travel?
Among six commodities P, Q, R, S, T and U, the price of Q is 1.5 times that of T. The price of U is four times that of P. The price of S is equal to the price of R. The price of P is 3.5 times that of R. The price of T is twice the price of R. The price of P is Rs. 70. What is the price of Q?
A certain sum of money was distributed among Darshana, Swati and Nivriti. Nivriti has Rs. 539 with her. If the ratio of the money distributed among Darshana, Swati and Nivriti is 5 : 6 : 7, what is the total sum of money that was distributed?
67 > 27 $ 9 < 4
If ‘A’ is replaced by ‘+’; if ‘B’ is replaced by ‘-‘; ‘C’ is replace by ‘÷’; and ‘D’ replaced by ‘x’, find the value of the following equation.
27B29A45C9D4
Find out the two signs to be interchanged for making following equation correct:
27 + 13 × 12 - 6 ÷ 3 = 50A number is subtracted from 4 times of it and then, the number obtained is added to its (the resultant’s) next number. If this gives the answer as 91, what was the original number?
When twice of a number added to 3 is multiplied by 5 and added to the number itself, it gives 158. What is the square of that number?
In a class of 72 students, the number of boys is twice the number of girls. Find the number of boys.
Two years ago, T was twice as old as P. P is thrice as old as R. In five years, P will be 29. What is the present age of T?
When a number is added to its multiple of 5 and its square, the sum of these three numbers is 91. Find the number.