At present, A is thrice as old as B. C is 5 years elder than B. The sum of the ages of A, B, and C is 75 years. The ratio of the age of B five years ago to the age of A three years from now is:
1 : 5
Given:
At present, A is thrice as old as B.
C is 5 years older than B.
The sum of the ages of A, B, and C is 75 years.
Formula Used:
Let the present age of B be B years.
The present age of A = 3B years.
The present age of C = B + 5 years.
Sum of the ages of A, B, and C = 75 years.
Age of B five years ago = B − 5 years.
Age of A three years from now = 3B + 3 years.
Ratio = (Age of B five years ago) / (Age of A three years from now)
Calculation:
Let the present age of B be B years.
The present age of A = 3B years.
The present age of C = B + 5 years.
Sum of the ages of A, B, and C = 75 years.
⇒ 3B + B + B + 5 = 75
⇒ 5B + 5 = 75
⇒ 5B = 70
⇒ B = 14
Age of B five years ago = B − 5 = 14 − 5 = 9 years.
Age of A three years from now = 3B + 3 = 3(14) + 3 = 42 + 3 = 45 years.
Ratio = 9 / 45
⇒ Ratio = 1 / 5
The ratio of the age of B five years ago to the age of A three years from now is 1 : 5.
Similar Questions
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Important Questions from Problem on Age
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