Assertion (A) : Curl of any vector is a vector. It gives normal vector which is perpendicular to both the plane and the parent vector. Reason (R) : The value of curl of H can be found by the expression : (Curl H)Normal = \(\lim_{\Delta S\to0}\dfrac{\oint \vec{H}\cdot d\vec{l}}{\Delta S}\) where $\Delta S$ is the planar area and $\overline{\text{dl}}$ is the line element. Select your answer using the codes given below.
Both (A) and (R) are true, but (R) is not the correct explanation of (A).
Let's analyze the Assertion (A) and the Reason (R) separately to determine their truth values and relationship.
Assertion (A): "Curl of any vector is a vector. It gives a normal vector which is perpendicular to both the plane and the parent vector."
Reason (R): "The value of curl of H can be found by the expression: \((\text{Curl H})_{\text{Normal}} = \lim_{\Delta S\to0}\dfrac{\oint \vec{H}\cdot d\vec{l}}{\Delta S}\)"
Relation between Assertion (A) and Reason (R):
Therefore, the correct option is: Both (A) and (R) are true, but (R) is not the correct explanation of (A).
In cylindrical coordinates, the Laplace equation holds the following expression :
\(\nabla\times\nabla\times\vec{A}\) is equal to :
A scalar function V is given by V = 2xyz2. The gradient of V is given by:
Match the following :
| List - I | List - II |
| (a) Curl operator | (i) Gradient |
| (b) Del operator | (ii) Volume to surface conversion |
| (c) Divergence tdeorem | (iii) Surface to line conversion |
| (d) Stokes tdeorem | (iv) Rotation |
Codes :
The product of generalized coordinates and its conjugate momentum has the dimension of
The divergence of vector xi +yj + zk is
The cross-section along two mutually perpendicular axes of a solid object are a circle and a square, respectively. The object is
If v = yz î + 3zx ĵ + z k̂, then curl v is
Which of the following is not a scalar quantity