Co-ordinates of mid point of a line AB is (14, 4). If co-ordinates of A is (- 4, - 22) then find the co-ordinates of B
(32, 30)
Understanding the concept of midpoint coordinates is crucial in coordinate geometry. The midpoint of a line segment connecting two points is the point exactly halfway between them. This problem involves finding the coordinates of B given the midpoint of line AB and the coordinates of A.
To determine the coordinates of B when given the midpoint and coordinates of A, we utilize the standard midpoint formula. This formula helps us relate the coordinates of the two endpoints to the coordinates of their midpoint.
Let the coordinates of point A be $$(x_1, y_1)$$, point B be $$(x_2, y_2)$$, and the midpoint M be $$(x_m, y_m)$$.
The midpoint formula is precisely defined as:
From the problem statement, we are provided with the following coordinates:
Our goal is to find the values of x and y for point B.
We will apply the midpoint formula specifically for the x-coordinate using the given values:
$$x_m = \frac{x_1 + x_2}{2}$$
Substitute the known values into the formula:
$$14 = \frac{-4 + x}{2}$$
To solve for x, first multiply both sides of the equation by 2:
$$14 \times 2 = -4 + x$$
$$28 = -4 + x$$
Now, add 4 to both sides to isolate x:
$$28 + 4 = x$$
$$x = 32$$
Thus, the x-coordinate of point B is 32.
Similarly, we will use the midpoint formula for the y-coordinate:
$$y_m = \frac{y_1 + y_2}{2}$$
Substitute the known y-values into the formula:
$$4 = \frac{-22 + y}{2}$$
Multiply both sides of the equation by 2:
$$4 \times 2 = -22 + y$$
$$8 = -22 + y$$
Now, add 22 to both sides to isolate y:
$$8 + 22 = y$$
$$y = 30$$
Thus, the y-coordinate of point B is 30.
Based on our calculations, the coordinates of point B are (32, 30). This process demonstrates how to effectively use the midpoint formula to find an unknown endpoint when the other endpoint and the midpoint are known.
| Point | x-coordinate | y-coordinate |
|---|---|---|
| A | -4 | -22 |
| M (Midpoint) | 14 | 4 |
| B | 32 | 30 |
The product of generalized coordinates and its conjugate momentum has the dimension of
The divergence of vector xi +yj + zk is
The cross-section along two mutually perpendicular axes of a solid object are a circle and a square, respectively. The object is
If v = yz î + 3zx ĵ + z k̂, then curl v is
Which of the following is not a scalar quantity