Arrange the following fractions in descending order : \(\frac{7}{8} \; ; \; \frac{19}{23} \; ; \; \frac{15}{17}\)
15/17 > 7/8 > 19/23
Convert each fraction to its decimal value for comparison.
\(\frac{7}{8} = 0.875, \ \frac{19}{23} \approx 0.826, \ \frac{15}{17} \approx 0.882\)
Arranging these decimal values from largest to smallest gives 0.882 > 0.875 > 0.826.
Hence, the descending order is \(\frac{15}{17} > \frac{7}{8} > \frac{19}{23}\).
Similar Questions
Arrange in ascending order:
$\frac{17}{18}$ , $\frac{29}{30}$ , $\frac{23}{24}$ ,$\frac{19}{20}$ .
Important Questions from Fractions
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is:
