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Question

Arrange in ascending order: 

$\frac{17}{18}$ , $\frac{29}{30}$ , $\frac{23}{24}$ ,$\frac{19}{20}$ .

This question was previously asked in
UPTET 2026 Paper 2 Social Studies Question Paper (3-Jul-2026) (Shift 1)
The correct answer is

$\frac{17}{18}$ < $\frac{19}{20}$ < $\frac{23}{24}$ < $\frac{29}{30}$

To arrange the fractions \(\frac{17}{18}\)\(\frac{29}{30}\)\(\frac{23}{24}\), and \(\frac{19}{20}\) in ascending order, we can compare them by converting them to decimals or by finding a common denominator. Here, we will convert these fractions to decimals for comparison: 

Convert \(\frac{17}{18}\) to decimal:

\[\frac{17}{18} \approx 0.9444\]

Convert \(\frac{29}{30}\) to decimal:

\[\frac{29}{30} \approx 0.9667\]

Convert \(\frac{23}{24}\) to decimal:

\[\frac{23}{24} \approx 0.9583\]

Convert \(\frac{19}{20}\) to decimal:

\[\frac{19}{20} = 0.95\]

Now, let's compare the decimals:

  • \(0.9444\)\) for \(\frac{17}{18}\)
  • \(0.95\)\) for \(\frac{19}{20}\)
  • \(0.9583\)\) for \(\frac{23}{24}\)
  • \(0.9667\)\) for \(\frac{29}{30}\)

Arranging these decimals in ascending order, we get:

  1. \(0.9444\)\) for \(\frac{17}{18}\)
  2. \(0.95\)\) for \(\frac{19}{20}\)
  3. \(0.9583\)\) for \(\frac{23}{24}\)
  4. \(0.9667\)\) for \(\frac{29}{30}\)

Therefore, the fractions in ascending order are:

\(\frac{17}{18} < \frac{19}{20} < \frac{23}{24} < \frac{29}{30}\)

Thus, the correct answer is:

\(\frac{17}{18} < \frac{19}{20} < \frac{23}{24} < \frac{29}{30}\)

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Important Questions from Fractions

  1. Which fraction among the following is the least ?

    \(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)

  2. Find the value of the following expression:

    \(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)

  3. Simplify the expression 441 ÷  \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)

  4. If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:

  5. The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\)  is:

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