Arrange in ascending order: $\frac{17}{18}$ , $\frac{29}{30}$ , $\frac{23}{24}$ ,$\frac{19}{20}$ .
$\frac{17}{18}$ < $\frac{19}{20}$ < $\frac{23}{24}$ < $\frac{29}{30}$
To arrange the fractions \(\frac{17}{18}\), \(\frac{29}{30}\), \(\frac{23}{24}\), and \(\frac{19}{20}\) in ascending order, we can compare them by converting them to decimals or by finding a common denominator. Here, we will convert these fractions to decimals for comparison:
Convert \(\frac{17}{18}\) to decimal:
\[\frac{17}{18} \approx 0.9444\]
Convert \(\frac{29}{30}\) to decimal:
\[\frac{29}{30} \approx 0.9667\]
Convert \(\frac{23}{24}\) to decimal:
\[\frac{23}{24} \approx 0.9583\]
Convert \(\frac{19}{20}\) to decimal:
\[\frac{19}{20} = 0.95\]
Now, let's compare the decimals:
Arranging these decimals in ascending order, we get:
Therefore, the fractions in ascending order are:
\(\frac{17}{18} < \frac{19}{20} < \frac{23}{24} < \frac{29}{30}\)
Thus, the correct answer is:
\(\frac{17}{18} < \frac{19}{20} < \frac{23}{24} < \frac{29}{30}\)
Which fraction among the following is the least ?
\(\frac{5}{11}, \frac{7}{12}, \frac{8}{13}, \frac{9}{17}\)
Find the value of the following expression:
\(\frac{{3 \div 1 \times 2 + 5 - 2}}{{3 \times 3 - 2}}\)
Simplify the expression 441 ÷ \(\left[270 \div \frac{3}{7}+\left(17\div \frac{1}{3}\right)-\left(8\frac{1}{2}-\frac{5}{2}\right)\right]\)
If the sum of two positive numbers is 65 and the square root of their product is 26, then the sum of their reciprocals is:
The value of \(9 \div [\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{6}\div(\frac{3}{4}-\frac{1}{3})\;of\;\frac{2}{9}]\) is: