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Question

Arrange the following communication systems in increasing order of their available commercial bandwidth :

1. Satellite Communication System
2. Amplitude Modulated System
3. Frequency Modulated System
4. Two-line transmission system

Correct sequence is

This question was previously asked in
UGC NET 2014 Paper 1 Question Paper (28-Dec-2014)
The correct answer is

4, 2, 3, 1

 Bandwidth tracks carrier frequency, so ranking these four by the band they occupy ranks them by capacity.

SystemFrequencyChannel bandwidth
Two-line transmissionAudio, up to a few hundred kHz~4 kHz per voice channel
AM broadcast540 – 1600 kHz (MF)10 kHz
FM broadcast88 – 108 MHz (VHF)200 kHz
Satellite4 – 30 GHz (SHF)36 MHz per transponder, 500 MHz total

Increasing order: two-line, AM, FM, satellite — that is 4, 2, 3, 1, option 1.

Why each step up is so large. A modulated channel can occupy at most a modest fraction of its carrier frequency, so a system working at 1 MHz cannot possibly carry a 1 MHz-wide signal, while one at 10 GHz can carry hundreds of megahertz without difficulty. Each move up the list is a jump of two or three orders of magnitude in carrier frequency, and the available bandwidth follows.

The AM to FM step is worth spelling out because both are broadcast services. AM's 10 kHz channel limits audio to about 5 kHz; FM's 200 kHz channel carries 15 kHz audio and spends the surplus on noise immunity through Carson's rule, \(B=2(\Delta f+f_{m})=2(75+15)=180\ \text{kHz}\). Twenty AM stations would fit in the space of one FM station.

The wire pair is last for a physical reason. Attenuation on a copper pair rises as \(\sqrt{f}\) because of the skin effect, and the untwisted pair also radiates and picks up interference as frequency climbs — which is why the traditional telephone channel is limited to 300–3400 Hz and multiplexed with FDM in 4 kHz slots.

Satellite links top the list not only because of frequency but because they are free of any conductor: the path is through space, so there is no \(\sqrt{f}\) loss at all. A single C-band satellite offers 500 MHz, divided into transponders of 36 MHz each, and reuses that spectrum twice over by orthogonal polarisation.

Hence, the increasing order is 4, 2, 3, 1.

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