Approximately, the coefficient of variation for the given data where Pearson's second measure of skewness = 0.42, arithmetic mean = 86 and median = 80, is:
50
Step 1 — Find the standard deviation using Pearson's second skewness:
\[Sk_p = \dfrac{3(\bar{x} - M)}{\sigma} \Rightarrow 0.42 = \dfrac{3(86 - 80)}{\sigma} = \dfrac{18}{\sigma}\]
\[\sigma = \dfrac{18}{0.42} \approx 42.857\]
Step 2 — Compute the coefficient of variation:
\[CV = \dfrac{\sigma}{\bar{x}} \times 100 = \dfrac{42.857}{86}\times 100 \approx 49.83\%\]
Rounded to the nearest option, CV ≈ 50.
The coefficient of kurtosis (β2) of standard normal distribution is equal to:
Half of the difference between the 75th percentile and 25th percentile is called:
The coefficient of variation and standard deviation for a dataset are 23 and 11, then the mean is approximately equal to:
What is the value of the z-score for x = 125 if population mean and variance are 121 and 4 respectively?
The Fisher's Index
If x i| f i, i = 1, 2 … n is a frequency distribution with standard deviation 15 and mean 30, the coefficient of variation will be equals to:
If Arithmetic mean and coefficient of variation of x are 10 and 40 respectively, then the variance of y = 10 - 2x is:
For the study purpose, the mean of the observations is 148 gm and standard deviation is 17.4 gm. Approximately, the coefficient of variation equals to:
For the recorded observation, the coefficient of variation is 20 and the variance is 16. The arithmetic mean is:
The coefficient of kurtosis (β2) of standard normal distribution is equal to:
Half of the difference between the 75th percentile and 25th percentile is called:
The coefficient of variation and standard deviation for a dataset are 23 and 11, then the mean is approximately equal to:
What is the value of the z-score for x = 125 if population mean and variance are 121 and 4 respectively?
The Fisher's Index