Amita is 2 years older than her friend Amrita. Amita's father is twice as old as
Amita and Amrita is twice as old as her sister. The ages of Amita's father and
Amrita's sister differs by 43 years. The difference between the ages of Amita and
Amrita is:
2
The correct answer is Option 3 i.e. 2.
Amita is 2 years older than her friend Amrita
Thus, difference = 2 years
Alternatively:-
Amrita’s age = x years
Amita’s age = x + 2
Amita’s father’s age = 2(x + 2)
Amrita’s sister’s age = x/2
⇒ 2(x + 2) - x/2 = 43
⇒ 4(x + 2) - x = 86
⇒ 4x + 8 - x = 86
⇒ 3x = 78
⇒ x = 26
Difference = x + 2 - x = 2 years
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.