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Question

If 2 times a son's age is added to his father's age, the sum is 36 years. If 2.5 times the father's age is added to the son's age, the sum is 72 years. What is the father's age (in years)?

The correct answer is
27

Age Word Problem Explained

This problem asks us to find the father's age based on two conditions relating his age and his son's age. We can solve this using algebra by setting up and solving a system of linear equations.

Setting Up Age Equations

First, let's define variables for the unknown ages:

  • Let $f$ represent the father's age (in years).
  • Let $s$ represent the son's age (in years).

Now, we translate the given information into mathematical equations:

Condition 1: "If 2 times a son's age is added to his father's age, the sum is 36 years."

This translates to the equation: $2s + f = 36$ (Equation 1)

Condition 2: "If 2.5 times the father's age is added to the son's age, the sum is 72 years."

This translates to the equation: $s + 2.5f = 72$ (Equation 2)

Our goal is to find the value of $f$.

Solving the System of Equations

We can solve this system using either substitution or elimination. Let's use the substitution method.

  1. Isolate one variable: From Equation 1, we can easily express the son's age ($s$) in terms of the father's age ($f$): $2s = 36 - f$ $s = \frac{36 - f}{2}$ $s = 18 - 0.5f$
  2. Substitute: Now substitute this expression for $s$ into Equation 2: $(18 - 0.5f) + 2.5f = 72$
  3. Solve for $f$: Simplify and solve the resulting equation for $f$: $18 + (-0.5f + 2.5f) = 72$ $18 + 2f = 72$ Subtract 18 from both sides: $2f = 72 - 18$ $2f = 54$ Divide by 2: $f = \frac{54}{2}$ $f = 27$

So, the father's age is 27 years.

Alternative Method: Elimination

We can also use the elimination method for practice.

Our system is:

1: $2s + f = 36$

2: $s + 2.5f = 72$

To eliminate $s$, we can multiply Equation 2 by 2:

$2 \times (s + 2.5f) = 2 \times 72$ $2s + 5f = 144$ (Equation 3)

Now, subtract Equation 1 from Equation 3:

$(2s + 5f) - (2s + f) = 144 - 36$

$2s + 5f - 2s - f = 108$

$4f = 108$

Solve for $f$:

$f = \frac{108}{4}$ $f = 27$

This method also gives the father's age as 27 years.

Verification of Ages

Let's check if our answer is correct by finding the son's age and plugging both ages back into the original conditions.

Using $s = 18 - 0.5f$: $s = 18 - 0.5 \times 27$ $s = 18 - 13.5$ $s = 4.5$

Check Condition 1: $2s + f = 2(4.5) + 27 = 9 + 27 = 36$. (Correct)

Check Condition 2: $s + 2.5f = 4.5 + 2.5(27) = 4.5 + 67.5 = 72$. (Correct)

Both conditions are satisfied, confirming our calculation.

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Important Questions from Age

  1. Five times the present age of P exceeds the present age of Q by 29 years. After 8 years, five times Q's age will be 17 years less than seven times P's age at that time. What is the present age (in years) of Q?
  2. 7 years ago, the age of a father was 13 years more than twice his son's age. After how many years, from now, will he be twice his son's age?
  3. If 2 times the mother's age is 26 years more than 4 times her daughter's age, and 3 times the daughter's age is 7 years less than the mother's age, then what is the difference (in years) between the ages of the mother and the daughter?

  4. Six times the present age of P exceeds the present age of Q by 11 years. After 10 years, three times Q's age will be 27 years less than six times P's age at that time. What is the present age (in years) of Q?
  5. Two times the present age of P exceeds the present age of Q by 41 years. After 7 years, nine times Q's age will be 24 years less than six times P's age at that time. What is the present age (in years) of Q?

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