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Question

The average age of a family of 6 members is 25 years with the youngest member being 8 years old. What was the average age (in years) of the family just before the birth of the youngest member?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is
20.4

Family Average Age Calculation Before Youngest Birth

This problem requires calculating the average age of the family members at a specific point in the past, just before the youngest member was born.

Step 1: Calculate the current total age of the family.

The family has 6 members with an average age of 25 years.

Current Total Age = Number of Members \(\times\) Average Age

Current Total Age = \(6 \times 25 = 150\) years.

Step 2: Determine the family composition and timeframe.

The youngest member is 8 years old. This means 8 years ago, this member was just born (age 0). At that time, the family consisted of the other 5 members.

Step 3: Calculate the total age of the 5 older members 8 years ago.

First, find the current total age of the 5 older members:

Total Age of 5 Older Members (Now) = Current Total Family Age - Age of Youngest Member

Total Age of 5 Older Members (Now) = \(150 - 8 = 142\) years.

Now, calculate their total age 8 years ago. Each of the 5 members was 8 years younger:

Total Age of 5 Older Members (8 years ago) = Total Age of 5 Older Members (Now) - (Number of Older Members \(\times\) 8 years)

Total Age of 5 Older Members (8 years ago) = \(142 - (5 \times 8) = 142 - 40 = 102\) years.

Step 4: Calculate the average age of the 5 members 8 years ago.

Average Age (8 years ago) = Total Age of 5 Older Members (8 years ago) / Number of Older Members

Average Age (8 years ago) = \(\frac{102}{5} = 20.4\) years.

Therefore, the average age of the family just before the birth of the youngest member was 20.4 years.

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Important Questions from Age

  1. The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:

  2. One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?

  3. In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?

  4. The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is

    A. 16 years

    B. 19 years

    C. 18 years

    D. 17 years

  5. A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.

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