A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.
10 years
Let the daughter’s present age be x years. Then the father's age is 3x years.
In 10 years, the daughter’s age will be x + 10 and the father’s age will be 3x + 10. According to the condition, 3x + 10 = 2(x + 10).
Solving for x: 3x + 10 = 2x + 20 → x = 10. So, the daughter’s present age is 10 years.
Important Questions from Age
The ratio of the ages of A and B, four years ago, was 4 : 5. Eight years from now, the ratio of the ages of A and B will be 11 : 13. What is the sum of their present ages?
The ratio of the present ages of A and B is 8 : 9. After 9 years, this ratio will become 19 : 21. C is 3 years younger to B. What is the present (in years) of C?
The ratio of the ages of A and B 8 years ago was 2 : 3. Four years ago, the ratio of their ages was 5 : 7. What will be the ratio of their ages 8 years from now?
The ratio of the present age of father to that of his son is 7 : 2. If after 10 years the ratio of their ages will become 9 : 4, then the present age of the father is:
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
