A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.
10 years
Let the daughter’s present age be x years. Then the father's age is 3x years.
In 10 years, the daughter’s age will be x + 10 and the father’s age will be 3x + 10. According to the condition, 3x + 10 = 2(x + 10).
Solving for x: 3x + 10 = 2x + 20 → x = 10. So, the daughter’s present age is 10 years.
Important Questions from Age
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
Namya got married 6 years ago. Now her age is 11⁄4times her age at the time of marriage. Her son’s present age is one-fifth of her present age. Find her son’s present age.
