Namya got married 6 years ago. Now her age is 11⁄4times her age at the time of marriage. Her son’s present age is one-fifth of her present age. Find her son’s present age.
6 years
Let Namya's age at the time of her marriage be x years. Since she got married 6 years ago, her current age is x+6 years. According to the problem, her current age is 11⁄4 times her age at the time of marriage. Therefore, we can express this relationship as:
x+6 = 11⁄4 × x
Convert 11⁄4 to an improper fraction:
11⁄4 = 5⁄4
So, the equation becomes:
x+6 = 5⁄4x
To eliminate the fraction, multiply both sides of the equation by 4:
4(x+6) = 5x
Expanding gives:
4x + 24 = 5x
Subtract 4x from both sides to solve for x:
24 = 5x - 4x
24 = x
This means Namya's age at the time of marriage was 24 years. Therefore, her present age is:
x + 6 = 24 + 6 = 30
Her son's present age is one-fifth of her present age:
Son's Age = 1⁄5 × 30 = 6
Thus, her son's present age is 6 years.
| Options | Age |
| 12 years | Incorrect |
| 5 years | Incorrect |
| 6 years | Correct |
| 20 years | Incorrect |
Important Questions from Age
The ages of two persons P and Q are in the ratio 5 : 7. Eight years ago, the ratio of P and Q was 7 : 13. The present ages of P and Q, respectively, are:
One year ago, the ratio of the ages of A and B was 4 : 3. The ratio of their ages, after 7 years from now, will be 9 : 7. What is the present age (in years) of B?
In 8 years, Subhash will be 3 times as old as he is now. After how many years will Subhash be 5 times as old as he is now?
The average ages of parents and two children are 30 years and 8 years respectively. The average age of the family is
A. 16 years
B. 19 years
C. 18 years
D. 17 years
A father is presently 3 times his daughter’s age. After 10 years he will be twice as old as her. Find the daughter’s present age.
