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Question

According to Karplus equation, the vicinal proton-proton coupling constant is minimum when the value of dihedral angle is

The correct answer is
$90^\circ$

Karplus Equation and Minimum Coupling

The Karplus equation is a fundamental concept in Nuclear Magnetic Resonance (NMR) spectroscopy that relates the magnitude of the coupling constant ($J$) between two vicinal nuclei (typically protons separated by three bonds) to the dihedral angle ($\phi$) between the C-H bonds involved.

This relationship helps chemists understand the three-dimensional structure (conformation) of molecules by analyzing the observed coupling constants.

Understanding the Karplus Equation Trend

The Karplus equation indicates that the magnitude of the vicinal coupling constant ($J$) varies significantly with the dihedral angle ($\phi$) between the coupled protons.

The general trend observed is:

  • Coupling is strongest (maximum $J$ value) when the dihedral angle is near $0^\circ$ and $180^\circ$.
  • Coupling is weakest (minimum $J$ value) when the dihedral angle is near $90^\circ$.

Identifying the Minimum Coupling Angle

Mathematically, the Karplus equation often involves terms like $\cos^2(\phi)$ and $\cos(\phi)$. Let's analyze the value of these terms at the given angles:

  • At $\phi = 0^\circ$: $\cos(0^\circ) = 1$, $\cos^2(0^\circ) = 1$.
  • At $\phi = 60^\circ$: $\cos(60^\circ) = 0.5$, $\cos^2(60^\circ) = 0.25$.
  • At $\phi = 90^\circ$: $\cos(90^\circ) = 0$, $\cos^2(90^\circ) = 0$.
  • At $\phi = 120^\circ$: $\cos(120^\circ) = -0.5$, $\cos^2(120^\circ) = 0.25$.
  • At $\phi = 180^\circ$: $\cos(180^\circ) = -1$, $\cos^2(180^\circ) = 1$.

The equation shows that the coupling constant ($J$) is minimized when the dihedral angle ($\phi$) is approximately $90^\circ$, as both the $\cos(\phi)$ and $\cos^2(\phi)$ terms contribute minimally or become zero at this angle, depending on the specific form of the equation used.

Therefore, the vicinal proton-proton coupling constant reaches its minimum value when the dihedral angle is $90^\circ$.

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