ABCD is a quadrilateral in which AB \(\parallel\) DC, and E and F are the mid points of the diagonals AC and BD, respectively. If AB = 23 cm, BC = 91 cm, DC = 35 cm, and AD = 62 cm, then what is the length (in cm) of EF?
6
In a trapezoid with AB parallel to DC, the segment joining the midpoints of the diagonals equals half the difference of the parallel sides: \(EF = \dfrac{|DC-AB|}{2}\).
\(EF = \dfrac{|35-23|}{2} = \dfrac{12}{2} = 6\).
Hence, the length of EF is 6 cm.
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