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Question

ABCD is a quadrilateral in which AB∥DC, and E and F are the mid points of the diagonals AC and BD, respectively. If AB = 14 cm, BC = 64 cm, DC = 72 cm, and AD = 47 cm, then what is the length (in cm) of EF?

This question was previously asked in
RRB NTPC 2025 Under Graduate CBT 1 Question Paper PDF (20-Jun-2026) (Shift 3)
The correct answer is

29

In a trapezoid with AB parallel to DC, the segment joining the midpoints of the diagonals equals half the difference of the parallel sides: \(EF = \dfrac{|DC-AB|}{2}\).

\(EF = \dfrac{|72-14|}{2} = \dfrac{58}{2} = 29\).

Hence, the length of EF is 29 cm.

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