ABCD is a quadrilateral in which AB∥DC, and E and F are the mid points of the diagonals AC and BD, respectively. If AB = 14 cm, BC = 64 cm, DC = 72 cm, and AD = 47 cm, then what is the length (in cm) of EF?
29
In a trapezoid with AB parallel to DC, the segment joining the midpoints of the diagonals equals half the difference of the parallel sides: \(EF = \dfrac{|DC-AB|}{2}\).
\(EF = \dfrac{|72-14|}{2} = \dfrac{58}{2} = 29\).
Hence, the length of EF is 29 cm.
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