ABC is a triangle right angled at B. Let D be the midpoint on AC. If BD = 6.5 cm, then what is AB 2 + BC 2 equal to?
169 square cm
The question describes a triangle ABC that is right-angled at B. We are given that D is the midpoint of the hypotenuse AC, and the length of the median BD is 6.5 cm. We need to find the value of \(AB^2 + BC^2\).
In a right-angled triangle, there are two fundamental properties that are crucial here:
We are given that BD = 6.5 cm.
Using the property of the median to the hypotenuse:
\(BD = \frac{1}{2} AC\)
Substituting the given value of BD:
\(6.5 = \frac{1}{2} AC\)
To find the length of AC, we multiply both sides by 2:
\(AC = 2 \times 6.5\)
\(AC = 13\) cm
Now we need to find \(AB^2 + BC^2\). According to the Pythagorean Theorem in the right-angled triangle ABC:
\(AB^2 + BC^2 = AC^2\)
We have found that AC = 13 cm. Substituting this value into the equation:
\(AB^2 + BC^2 = (13)^2\)
\(AB^2 + BC^2 = 13 \times 13\)
\(AB^2 + BC^2 = 169\)
The value of \(AB^2 + BC^2\) is 169 square cm.
| Given Information | Property Used | Calculation | Result |
|---|---|---|---|
| Triangle ABC, right-angled at B | Median to hypotenuse BD = 6.5 cm | Median property: \(AC = 2 \times BD\) | \(AC = 2 \times 6.5 = 13\) cm |
| Triangle ABC, right-angled at B | Required: \(AB^2 + BC^2\) | Pythagorean Theorem: \(AB^2 + BC^2 = AC^2\) | \(AB^2 + BC^2 = (13)^2 = 169\) |
Therefore, \(AB^2 + BC^2\) is equal to 169 square cm.
| Concept | Description | Formula/Property |
|---|---|---|
| Right-Angled Triangle | A triangle with one angle measuring 90 degrees. | - |
| Hypotenuse | The side opposite the right angle; it is the longest side. | - |
| Pythagorean Theorem | In a right triangle, the square of the hypotenuse length is the sum of the squares of the other two sides. | \(a^2 + b^2 = c^2\) (where c is hypotenuse) |
| Median to Hypotenuse | The line segment from the right angle vertex to the midpoint of the hypotenuse. | Length of median = \(\frac{1}{2}\) \(\times\) Length of hypotenuse |
| Midpoint | A point that divides a line segment into two equal parts. | - |
It's also useful to know the converses of these properties:
These converses help in identifying right triangles based on side lengths or median lengths.
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