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Question

A Zener diode is used in a voltage regulator circuit as shown below. Its breakdown voltage is 15 V. What is the current flowing through the Zener diode?

The correct answer is

5 mA

The total voltage applied is 25 V. The voltage across the resistor is (25V - 15V) = 10V. Using Ohm's law, the current through the 500Ω resistor is I = V/R = 10V / 500Ω = 0.02 A = 20 mA. The current through the 1kΩ resistor is I = 15V / 1000Ω = 15 mA. Thus, the Zener diode current is 20 mA - 15 mA = 5 mA.

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Important Questions from Semiconductor and Electronic Devices

  1. If the forward voltage in a p-n junction diode is increased, the width of the depletion region:

  2. Two identical thin metal plates are given charges q1 and q2 (q2 < q1) respectively. If they are now brought close together to form a parallel plate capacitor with a capacitance 'C', then the potential difference between the plates is:

  3. Displacement current (id) = ω0E / dt. Where symbols have their usual meanings. Which of the following options gives correct equation for displacement current?

  4. Choose the correct experimental circuit arrangement for studying V-I characteristics of a p-n junction diode in forward bias:

  5. During the p-n junction formation, when an electron diffuses from n → p, it leaves behind an:

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