A uniform meter scale weighs 50g. It is pivoted at the 70cm mark. Where should a 40 g mass be placed so that the scale is in equilibrium?
At the 95 cm mark
A body stays in rotational equilibrium when the clockwise and anticlockwise moments about the pivot are equal (principle of moments).
A uniform scale has its weight acting at its centre, the 50 cm mark. Distance from pivot = 70 - 50 = 20 cm.
Moment of the scale = 50 × 20 = 1000 g·cm
The 40 g mass must sit on the other side: 40 × d = 1000
d = 25 cm, so its position is 70 + 25 = 95 cm
Check: 40 × 25 = 1000 g·cm = 50 × 20 g·cm, so the moments balance.
Hence, At the 95 cm mark.
Similar Questions
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Important Questions from Levers and Simple Machines
Which one of the following is CORRECT statement about Simple machines?
Efficiency of Simple machine is the ratio of:
- The force applied to overcome a load is called ______.
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- Choose the option which does NOT belong to the category of simple machine
