Efficiency of Simple machine is the ratio of:
Output to input
The efficiency of any machine, including a simple machine, is a measure of how much useful work is obtained from the work put into it. It tells us how well the machine converts input energy into useful output work.
In the context of machines, efficiency is formally defined as the ratio of the useful output work done by the machine to the total input work done on the machine. This ratio is often expressed as a percentage by multiplying by 100.
The formula for efficiency ($\eta$) is:
$\eta = \frac{\text{Useful Output Work}}{\text{Input Work}}$
Since work done can be related to power and time, efficiency can also be expressed as the ratio of useful output power to total input power, assuming the time interval is the same:
$\eta = \frac{\text{Useful Output Power}}{\text{Input Power}}$
Let's look at the given options:
Based on the definitions in mechanics, the efficiency of a simple machine is correctly represented by the ratio of the output (useful work or power) to the input (total work or power).
Therefore, the correct ratio for the efficiency of a simple machine is Output to Input.
Which one of the following is CORRECT statement about Simple machines?
In a lever-operated compressor servicing tool (Class 1 lever), if the load arm length is decreased while the effort arm length is kept constant, what will be the effect on its mechanical advantage?