This problem involves calculating the train's length using the times it takes to cross two bridges of different lengths. We utilize the fundamental relationship: Distance = Speed × Time.
The total distance the train covers equals the bridge length plus the train length.
Since the train's speed $S$ is constant, we can set up an equation by equating the expressions for $S$ derived from both scenarios:
From the first scenario: $S = \frac{600 + L}{80}$
From the second scenario: $S = \frac{200 + L}{40}$
Equating these speeds:
$ \frac{600 + L}{80} = \frac{200 + L}{40} $
To solve for $L$, we first simplify the equation by multiplying both sides by 40:
$ \frac{600 + L}{2} = 200 + L $
Next, we distribute the 2 on the left side:
$ 600 + L = 400 + 2L $
Now, we rearrange the terms to isolate $L$:
$ 600 - 400 = 2L - L $
Finally, we find the value of $L$:
$ L = 200 $
Therefore, the length of the train is 200 m.
A train is to cover 370 km at a uniform speed. After running 100 km, the train could run at a speed 5 km/h less than its normal speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
A train travelling at 36 km/h crosses a pole in 25 seconds. How much time (in seconds) will it take to cross a bridge 250 m long?
A train covers 450 km at a uniform speed. If the speed had been 5 km/h more, it would have taken 1 hour less to cover the same distance. How much time will it take to cover 315 km at its usual speed?
A train crosses a pole in 12 sec, and a bridge of length 170 m in 36 sec. Then the speed of the train is:
The ratio of the speeds of two trains is 2 : 7. If the first train runs 250 km in 5 hours, then the sum of the speeds (in km/h) of both the trains is: