A train A passes a fixed pole in 24 seconds. The same train completely crosses another train B of length 150 m coming from the opposite direction in 20 seconds. Train B’s speed is 54 km/h. Find the length and the speed of train A.
900 m and 135 km/h
Let the length of train A be \(L\) metres and its speed be \(v\) m/s.
Passing a pole: \(L = 24v\).
Speed of train B = 54 km/h = \(54\times\tfrac{5}{18}=15\) m/s.
Trains move in opposite directions, so relative speed = \(v+15\) m/s and combined distance to cross = \(L+150\) m.
Hence \(\dfrac{L+150}{v+15}=20\ \Rightarrow\ L+150 = 20v+300\).
Substituting \(L=24v\): \(24v+150 = 20v+300 \Rightarrow 4v = 150 \Rightarrow v = 37.5\) m/s.
So speed of A = \(37.5\times\tfrac{18}{5}=135\) km/h and \(L=24\times 37.5=900\) m.
Hence, train A is 900 m long with a speed of 135 km/h.
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