A student incorrectly calculates a positive object distance while using the lens formula for a real object. Based on the sign convention, what is the conceptual error in this calculation?
Object distance should be negative for a real object as it is placed to the left of the lens.
In the New Cartesian sign convention for lenses, the optical centre is taken as the origin and the object is placed on the left of the lens, so light travels from left to right. Distances measured in the direction of the incident light (to the right) are positive, and distances measured against it (to the left) are negative.
A real object lies on the left of the lens, so its distance is measured against the direction of incident light and the object distance \(u\) must be negative. Taking it as positive is therefore the conceptual error.
The sign of the object distance depends only on the side of the lens where the object lies, not on the focal length or on the object height (heights have their own sign rule: upward positive, downward negative). Saying the object distance is always positive for a real object repeats the student's error.
Hence, Object distance should be negative for a real object as it is placed to the left of the lens.
An object is placed at a distance of 10 cm from a convex lens. The lens produces a real and magnified image with a magnification \(-3\). What is the position of the image?
An eye lens forms a real, inverted image 2 cm behind the retina for a distant object. What error in the eye's structure could cause this situation?
A beam of white light passes through a glass prism and forms a spectrum on a screen. If you place a second identical prism after the first, inverted with respect to it, what will happen to the spectrum?
If c is the speed of light in air and v is the speed of light in a medium, how is the refractive index nm of that medium defined?
An object is placed 10 cm from a diverging lens with a focal length of 15 cm. What is the position of the image formed?
If the object is placed at the focus of a convex lens, the image will be:
A student places an object 30 cm in front of a convex lens of focal length 15 cm. Based on the lens formula, where will the image be formed?
A child’s near point is 50 cm, but normal near point for a human eye is 25 cm. What is the required power of the lens to correct the child's near point?
A ray of light enters a glass prism from air. Which change occurs to the speed of the light as it enters the prism?
A concave lens has a focal length of 30 cm. At what distance should the object from the lens be placed so that it forms an image at 20 cm from the lens?
Who was the first one to use a glass prism to obtain the spectrum of sunlight?
Twinkling of stars is due to:
In which a convex mirror is used?
A. Rear View mirrors in vehicles
B. Glass windows
C. Makeup Mirror
D. Kaleidoscope
An object is placed 10 cm in front of a lens. The image formed is real, inverted and of same size as the object. What is the focal length and nature of the lens?
The power of a lens is -2.5 D. The type of lens and its focal length are respectively: