A student adds \(\tfrac35\) unit of a solution, then adds 0.4 unit of the same solution, and finally removes \(\tfrac1{10}\) unit. What is the net change in the quantity of the solution?
increase of 0.9 unit
Net change: \(\tfrac35+0.4-\tfrac{1}{10} = 0.6+0.4-0.1 = 0.9\).
Hence, the net change in the quantity of the solution is an increase of 0.9 unit.
What will the value of the following be (correct to three decimal points)?
$160.342 - 32.124$
Arrange the following numbers in their increasing order.
(1) $-0.96$
(2) $0.83$
(3) $0.24$
(4) $-0.64$
(5) $0.58$
Simplify the given expression.
$9 \times 0.9 \times 0.09 \times 0.009 \times \frac{1}{0.3} \times \frac{1}{0.03} \times \frac{1}{0.003}$
What is the result when 0.129129129… is converted to a fraction?
Which of the following statement(s) is/are correct?
I. (3/11) > 0.3
II. (7/8) > 0.86
The value of \(1.\overline{3}+0.\overline{69}-0.5\overline{23}\) is equal to:
The value of \(0.\bar 4 + 0.5 \bar 9 - 0.4 \overline{23}\) is equal to:
Find the sum of \(\frac{0.01}{0.1}+\frac{0.1}{0.01}\)