The problem involves calculating the amount of paint needed for several smaller spheres formed by melting a larger sphere, considering volume loss and changes in radius.
Let the radius of the large sphere be R and the radius of each smaller sphere be r. We are given that r = R/10.
The surface area of a sphere is given by the formula A = 4π * radius2.
The ratio of the surface area of a small sphere to the large sphere is:
\( \frac{A_{small}}{A_{large}} = \frac{4\pi r^2}{4\pi R^2} = \left(\frac{r}{R}\right)^2 \)
Substituting r = R/10:
\( \frac{A_{small}}{A_{large}} = \left(\frac{R/10}{R}\right)^2 = \left(\frac{1}{10}\right)^2 = \frac{1}{100} \)
This means the surface area of one small sphere is 1/100th of the large sphere's surface area. Since paint usage is proportional to surface area, one small sphere needs 1/100th the paint of the large sphere.
The volume of a sphere is given by the formula V = (4/3)π * radius3.
The ratio of the volumes is:
\( \frac{V_{small}}{V_{large}} = \frac{(4/3)\pi r^3}{(4/3)\pi R^3} = \left(\frac{r}{R}\right)^3 \)
Substituting r = R/10:
\( \frac{V_{small}}{V_{large}} = \left(\frac{1}{10}\right)^3 = \frac{1}{1000} \)
So, the volume of one small sphere is 1/1000th of the large sphere's volume.
During melting, 5% of the volume is lost. This means 95% of the large sphere's volume is available to form smaller spheres.
Volume available = 0.95 * Vlarge.
The number of smaller spheres (N) is:
\( N = \frac{\text{Volume available}}{V_{small}} = \frac{0.95 \times V_{large}}{V_{large} / 1000} = 0.95 \times 1000 = 950 \)
Therefore, 950 smaller spheres are formed.
Paint needed for the large sphere = 14 liters. This corresponds to Alarge.
Paint needed for one small sphere corresponds to Asmall.
Paint per small sphere = 14 liters * (Asmall / Alarge) = 14 * (1/100) = 0.14 liters.
Total paint needed for all 950 smaller spheres:
Total Paint = Number of small spheres * Paint per small sphere
Total Paint = 950 * 0.14 liters
Total Paint = 950 * (14 / 100) liters
Total Paint = 9.5 * 14 liters
Total Paint = 133 liters.
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
Which of the following is a geometrical figure with a three-dimensional geometry that has eight vertices and six rectangular faces?
A conical tent has a base radius of 14 m and a height of 48 m. How many cubic meters of air can it hold? (Use \(\pi\) = )
The circumference of the base of a solid right circular cylinder is 88 cm and its height is 150 cm. What is the volume (in cm3) of the cylinder?
A solid right circular cone is 7 cm high, and the radius of its base is 22.2 cm. It is melted and recast into a right circular cone with radius of its base 3.7 cm. Then the height (in cm) of the cone is ______.
A plane parallel to the base divides a cone of height 40 cm into two parts. If the volumeof the upper smaller cone formed is \(\frac{1}{64}\) of the volume of the original cone, calculate the height of the plane from the base of the cone.
In a workshop, you need to fill a cylindrical tank with a liquid. The tank has a diameter of 1 meter and a height of 2 meters. Which method will give you the most accurate measurement of the tank's volume before filling it?
If the volume of a cube is 3375 cm3, what is the length of one side?
The total surface area of a cylinder is given by ________.
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
Which of the following is a geometrical figure with a three-dimensional geometry that has eight vertices and six rectangular faces?
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)