A plane parallel to the base divides a cone of height 40 cm into two parts. If the volume of the upper smaller cone formed is \(\frac{1}{64}\) of the volume of the original cone, calculate the height of the plane from the base of the cone.
30 cm
For similar cones, the ratio of volumes equals the cube of the ratio of their heights.
Given the upper small cone is 1/64 of the whole: \(\left(\frac{h}{40}\right)^{3}=\frac{1}{64}\).
Taking cube roots: \(\frac{h}{40}=\frac{1}{4}\), so h = 10 cm (the small cone's height measured from the apex).
The plane's height from the base = total height − small cone height = 40 − 10 = 30 cm.
Hence, the answer is 30 cm.
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