A cylindrical tank of diameter 2 m and height 3.5 m is filled with petrol. Using π = $\frac{22}{7}$, the volume is:
11 m3
The tank is a right circular cylinder, so its volume is found from the formula \(V=\pi r^{2}h\), where r is the radius of the base and h is the height.
The diameter is given as 2 m, and the radius is half the diameter, so \(r=\frac{2}{2}=1\ \text{m}\), while the height is \(h=3.5\ \text{m}\).
Using the value \(\pi=\frac{22}{7}\) as instructed, substitute the numbers: \(V=\frac{22}{7}\times 1^{2}\times 3.5\).
Since \(1^{2}=1\), this simplifies to \(V=\frac{22}{7}\times 3.5\).
Note that \(\frac{3.5}{7}=0.5\), so the expression becomes \(V=22\times 0.5=11\ \text{m}^{3}\).
The height of 3.5 m combined with a unit radius makes the arithmetic clean, and none of the other listed values (9, 12 or 15 m3) match this correct computation.
Hence, the answer is 11 m3.
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Important Questions from 3-D Mensuration
Find the total surface area of a closed cylinder having a base radius of 70 m and a height of 110 m. [Use π = \(22\over7\)]
- The curved surface area of a cylinder is half of its total surface area. If its height is 195 cm, then find its diameter (in cm).
The diameter of the base and slant height of a right circular cone are 30 cm and 113 cm, respectively. Find the volume (in cm³) of the given cone.
(Use $\pi = \frac{22}{7}$)- A cylindrical rod has an curved surface area of $4,900 \text{ cm}^2$. If the length of the rod is 97 cm, then the radius (in cm) of the rod, correct to two places of decimal, is:
Take $\pi = \frac{22}{7}$ - The volume (in $m^3$) of a cube, each of whose edges is 42 m, is:
