A sinusoidal alternating voltage of 50 Hz has an RMS value of 200 V. Find the maximum value and wavelength.
282.2 V, 314 rad/sec
The problem asks us to find the maximum value and "wavelength" for a sinusoidal alternating voltage with a given RMS value and frequency. In the context of alternating current (AC) circuits, the term "wavelength" is typically associated with travelling waves or transmission lines and represents a spatial dimension. However, the provided options include values in "rad/sec", which is the unit for angular frequency ($\omega$). It is highly probable that "wavelength" in the question is a typo and it is intended to mean "angular frequency". We will proceed by calculating both the maximum value and the angular frequency of the given sinusoidal alternating voltage.
We are given the following information:
For a sinusoidal alternating voltage, the relationship between the RMS value ($V_{rms}$) and the maximum value (or peak value, $V_m$) is given by the formula:
$$V_m = V_{rms} \times \sqrt{2}$$
Let's plug in the given RMS value:
$$V_m = 200 \text{ V} \times \sqrt{2}$$
Using the approximate value $\sqrt{2} \approx 1.4142$:
$$V_m \approx 200 \times 1.4142 \text{ V}$$
$$V_m \approx 282.84 \text{ V}$$
This is the calculated maximum value based on the given RMS value of 200 V.
The angular frequency ($\omega$) of an alternating voltage is related to its linear frequency ($f$) by the formula:
$$\omega = 2 \pi f$$
where $\pi$ is the mathematical constant pi (approximately 3.14159).
Let's plug in the given frequency:
$$\omega = 2 \times \pi \times 50 \text{ Hz}$$
$$\omega = 100 \pi \text{ rad/sec}$$
Using the approximate value $\pi \approx 3.14$:
$$\omega \approx 100 \times 3.14 \text{ rad/sec}$$
$$\omega \approx 314 \text{ rad/sec}$$
This is the calculated angular frequency based on the given frequency of 50 Hz.
Our calculations yielded:
Let's look at the options provided:
Option 3 provides 282.2 V for the maximum value and 314 rad/sec for the angular frequency. Our calculated maximum value (282.84 V) is very close to 282.2 V, and our calculated angular frequency (314 rad/sec) matches exactly with 314 rad/sec when using $\pi \approx 3.14$. Therefore, option 3 is the closest match based on standard calculations.
Based on our analysis and assuming "wavelength" refers to angular frequency:
| Parameter | Symbol | Relationship | Example (f=50 Hz, Vrms=200V) |
|---|---|---|---|
| Linear Frequency | f | Given in Hz | 50 Hz |
| Angular Frequency | ω | ω = 2πf | 314 rad/sec (≈ 100π) |
| RMS Value | Vrms | Vrms = Vm / √2 | 200 V |
| Maximum Value (Peak) | Vm | Vm = Vrms × √2 | ≈ 282.8 V |
Understanding the different parameters of a sinusoidal AC voltage is crucial in electrical engineering. Here's a bit more detail:
The ratio of resistance to impedance is ______.
If voltage is measured across an AC mains open switch, the meter will read:
What is the relation between line voltage and phase voltage in a delta connection?
If the value of phase voltage in a star connected circuit is 240 V, then its line voltage is ______.
In which of the following connections do we have common neutral point?
What is meant by line voltage?
If apparent power is found equal to active power, then the system power factor is:
When a capacitor load is connected, the power factor is:
When an inductive load is connected, the power factor is:
To find real power, the apparent power has to be multiplied by:
The ratio of resistance to impedance is ______.
If voltage is measured across an AC mains open switch, the meter will read:
The phase voltage of a star-connected, three-phase circuit is 200 V. The line voltage will be
What is the phase difference between the line voltage and phase voltage in a star-connected load?