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Question

A shopkeeper has 2220 kg of rice. A part of which he sells at a 20% profit and the rest at a 12% profit. He gains 18% on the whole. The quantity ( in kg ) sold at a 12% profit is:

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

555

Calculating Rice Quantity Sold at Different Profits

This problem involves a shopkeeper selling a total quantity of rice in two parts, each at a different profit percentage, resulting in an overall profit percentage. We need to find the specific quantity sold at one of the given profit rates.

This type of problem can be efficiently solved using the concept of Alligation or weighted averages. The Alligation method helps us find the ratio in which two quantities with different characteristics (here, profit percentages) are mixed to get a mixture with an average characteristic.

Understanding the Alligation Method for Profit

In this scenario, the two characteristics are the profit percentages on the two parts of the rice, and the average characteristic is the overall profit percentage on the total quantity of rice. The method works as follows:

  1. Write down the two individual profit percentages.
  2. Write down the overall average profit percentage in the middle.
  3. Find the difference between the overall profit and each individual profit. These differences give the ratio of the quantities sold at the respective profit percentages.

Applying Alligation to the Shopkeeper's Rice Sale

  • Profit percentage on Part 1: 20%
  • Profit percentage on Part 2: 12%
  • Overall average profit percentage: 18%

Let's set up the alligation cross:

Higher Profit (%) Lower Profit (%)
20 Overall Profit (%)
18
12
 
Difference (Overall - Lower) Difference (Higher - Overall)
\(18 - 12 = 6\) \(20 - 18 = 2\)

The ratio of the quantity sold at the lower profit (12%) to the quantity sold at the higher profit (20%) is the inverse of the differences calculated. That is:

\(\text{Quantity at 12% Profit} : \text{Quantity at 20% Profit} = (20 - 18) : (18 - 12)\)

\(\text{Ratio} = 2 : 6\)

This ratio can be simplified by dividing both parts by their greatest common divisor, which is 2:

\(\text{Ratio} = \frac{2}{2} : \frac{6}{2} = 1 : 3\)

So, for every 1 part of rice sold at 12% profit, 3 parts were sold at 20% profit.

Calculating the Quantities Sold

The total ratio parts are \(1 + 3 = 4\). This means the total quantity of rice (2220 kg) is divided into 4 equal parts according to this ratio.

The quantity sold at 12% profit corresponds to 1 part of the ratio.

The quantity sold at 20% profit corresponds to 3 parts of the ratio.

Total quantity of rice = 2220 kg

Quantity sold at 12% profit \( = \frac{\text{Ratio part for 12%}}{\text{Total ratio parts}} \times \text{Total quantity} \)

Quantity sold at 12% profit \( = \frac{1}{4} \times 2220 \text{ kg} \)

Let's perform the calculation:

\[ \frac{1}{4} \times 2220 = \frac{2220}{4} \] \[ \frac{2220}{4} = 555 \]

So, the quantity of rice sold at a 12% profit is 555 kg.

For completeness, the quantity sold at 20% profit would be:

Quantity sold at 20% profit \( = \frac{3}{4} \times 2220 \text{ kg} = 3 \times 555 \text{ kg} = 1665 \text{ kg} \)

Check: \(555 \text{ kg} + 1665 \text{ kg} = 2220 \text{ kg}\), which is the total quantity.

The question asks for the quantity (in kg) sold at a 12% profit, which we calculated to be 555 kg.

Final Answer Summary

By using the alligation method, we found the ratio of quantities sold at 12% and 20% profit to be 1:3. Applying this ratio to the total quantity of 2220 kg, we determined the quantity sold at a 12% profit.

Quantity sold at 12% profit = 555 kg.


Revision Table: Key Concepts Revisited

Concept Explanation Application in Problem
Profit Percentage Profit expressed as a percentage of the cost price. Given as 20%, 12%, and 18% (overall).
Overall Profit Total profit on the entire quantity, usually expressed as a percentage of the total cost price. Given as 18% on the whole.
Alligation Method A technique used to find the ratio in which two ingredients (or quantities with different characteristics) are mixed to produce a mixture with a desired mean characteristic. Used to find the ratio of rice quantities sold at 12% and 20% profit.
Ratio and Proportion Dividing a total quantity according to a given ratio. Used to split the total 2220 kg into quantities corresponding to the 1:3 ratio found by alligation.


Additional Information: Why Alligation Works

The alligation method is derived from the weighted average concept. Let \(Q_1\) be the quantity sold at profit \(P_1\) and \(Q_2\) be the quantity sold at profit \(P_2\). The total profit is \(Q_1 \times P_1 + Q_2 \times P_2\). The total quantity is \(Q_1 + Q_2\). The overall average profit \(P_{avg}\) is given by:

\[ P_{avg} = \frac{Q_1 \times P_1 + Q_2 \times P_2}{Q_1 + Q_2} \]

Rearranging this equation gives:

\[ P_{avg}(Q_1 + Q_2) = Q_1 P_1 + Q_2 P_2 \] \[ Q_1 P_{avg} + Q_2 P_{avg} = Q_1 P_1 + Q_2 P_2 \] \[ Q_2 P_2 - Q_2 P_{avg} = Q_1 P_{avg} - Q_1 P_1 \] \[ Q_2 (P_2 - P_{avg}) = Q_1 (P_{avg} - P_1) \]

Assuming \(P_1 > P_{avg} > P_2\), this becomes:

\[ Q_2 (P_{avg} - P_2) = Q_1 (P_1 - P_{avg}) \]

This shows the inverse relationship between the quantities and the differences in profit percentages from the average. The ratio \(Q_1 : Q_2\) is indeed \((P_{avg} - P_2) : (P_1 - P_{avg})\), which is exactly what the alligation diagram represents.

In our problem, \(P_1 = 20\%\), \(P_2 = 12\%\), and \(P_{avg} = 18\%\). Note that we used \(P_1 = 20\%\) and \(P_2 = 12\%\) labels slightly differently in the alligation table for clarity with "Higher" and "Lower", but the calculation of differences remains consistent. The difference \(P_{avg} - P_2 = 18 - 12 = 6\) corresponds to the quantity \(Q_1\) (at 20%), and the difference \(P_1 - P_{avg} = 20 - 18 = 2\) corresponds to the quantity \(Q_2\) (at 12%). So the ratio \(Q_1 : Q_2\) is \(6 : 2\), or \(3 : 1\). This means Quantity at 20% Profit : Quantity at 12% Profit = 3 : 1. This matches our earlier finding using the inverse ratio \(1:3\) for \(Q_{12} : Q_{20}\). The method is consistent and provides a quick way to solve such mixture problems involving profit percentages.

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Similar Questions

  1. A mixture of acid and water contains 20 percent acid. When 10 litres of water is added to the mixture, then the percentage of acid becomes 15 percent. What is the original quantity of mixture ?

  2. A milkman buys milk at Rs. 24 per litre. He adds 1/5 of water to it and sells the mixture at Rs. 32 per litre. What will be his gain (in %)?

  3. A vessel is filled with liquid, 5 parts of which are water and 11 parts syrup. What part of the mixture must be drawn off and replaced with water so that the mixture may be syrup and water in the ratio 3 ∶ 2?

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Important Questions from Mixture Problems

  1. If the ratio of alcohol and water in a mixture of 85 litres is 11 ∶ 6. How much water should be added to make the ratio 5 ∶ 3?

  2. Two bottles A and B contain diluted acid. In bottle A, the amount of water is double the amount of acid while in bottle B, the amount of acid is 3 times that of water. How much mixture(in litres) should be taken from each bottle A and B respectively in order to prepare 5 liters diluted acid containing an equal amount of acid and water?

  3. A solution of milk and water contains milk and water in the ratio of 3 : 2. Another solution of milk and water contains milk and water in the ratio of 2 : 1. Forty litres of the first solution is mixed with 30 litre of the second solution. The ratio of milk and water in the resultant solution is:

  4. A 70 litre mixture has liquids A and B in the ratio 5 ∶ 9. How many litres of liquid A must be added so that the ratio becomes 2 ∶ 3?

  5. 60 kg of an alloy A is mixed with 80 kg of alloy B to get a new alloy. If alloy A has zinc and copper in the ratio 7 : 5 and alloy B has zinc and copper in the ratio 3 : 7, then what is the weight of zinc in the new alloy?

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