A set of data presented in the form of a frequency distribution table with class intervals and their respective frequencies had a mode of 48.5. The lower boundary of the modal class was 46.5; the frequency of the modal class was 34; the frequency of the class interval just preceding the modal class was 32 and the frequency of the class interval just succeeding the modal class was 25. What was the width of the modal class?
11
The formula to calculate the width of the modal class is: \[ \text{Width} = \frac{\text{Modal class frequency} - \text{Preceding frequency}}{\text{Modal class frequency} - \text{Succeeding frequency}} \] Substituting the given values: \[ \frac{34 - 32}{34 - 25} = 11 \]
Similar Questions
Find the mean proportional of 36 and 100.
Important Questions from Mean Proportional
What number must be added to each of the numbers 15, 9 and 5 so that the resulting numbers may be in a continued proportion ?
When x is subtracted from each of 43, 38, 11 and 10, then the numbers so obtained in this order are in proportion. What is the mean proportional between (11x + 3) and (9x - 2) ?
Find the mean proportional between 4 and 900.
If 22, x, 88 are in a continued proportion, find the value of x.
A. 24
B. 33
C. 44
D. 36
The arithmetic mean and geometric mean of two numbers are 7 and 2√10 respectively, then find the numbers.
