A set of data presented in the form of a frequency distribution table with class intervals and their respective frequencies had a mode of 48.5. The lower boundary of the modal class was 46.5; the frequency of the modal class was 34; the frequency of the class interval just preceding the modal class was 32 and the frequency of the class interval just succeeding the modal class was 25. What was the width of the modal class?
11
The formula to calculate the width of the modal class is: \[ \text{Width} = \frac{\text{Modal class frequency} - \text{Preceding frequency}}{\text{Modal class frequency} - \text{Succeeding frequency}} \] Substituting the given values: \[ \frac{34 - 32}{34 - 25} = 11 \]
The mean proportional of 4a2 and x is \(\frac{1}{5a^2}\), where a is a positive number. Then the value of x is _____.
The marks obtained by 15 students out of a maximum of 25 in a test are given as 13, 11, 16, 15, 18, 12, 13, 14, 10, 22, 15, 21, 20, 17 and 24. Find the product of the modes of this set of data.
Find the mean proportional of 12.96 and 0.16.
Find the mean proportional of 36 and 100.
When x is subtracted from each of 24, 30, 36 and 46, the numbers so obtained in this order, are in proportion. What is the mean proportional between (2x + 3) and (3x + 2)?
What is the mean proportional of 40 and 90?
What is the mean proportional between 3 and 27?
The mean proportion of the two numbers is 9 and the third proportion is 243. What will be the average of those numbers?
The mean proportional between 35 and a certain number N is four times the mean proportional between 14 and 30. The number N is: