A person travels at the speed of 12kmph, 8kmph and 6kmph on the surface of an equilateral triangle. Find the average speed of his journey. (In Kmph)
8
The three sides of an equilateral triangle are equal, so equal distances d are covered at 12, 8 and 6 km/h.
Average speed for equal distances = \(\frac{3}{\frac{1}{12} + \frac{1}{8} + \frac{1}{6}}\).
\(\frac{1}{12} + \frac{1}{8} + \frac{1}{6} = \frac{2 + 3 + 4}{24} = \frac{9}{24}\).
Average speed = \(3 \times \frac{24}{9} = 8\) km/h.
Hence, the average speed is 8 km/h.
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