A person travels along the sides of an equilateral triangular field at speeds of 36 kmph, 30 kmph and 45 kmph. Find his average speed.
36 kmph
The sides of an equilateral triangle are equal, so equal distances are covered at each speed and the average speed is the harmonic mean.
Average speed = \(\frac{3}{\frac{1}{36} + \frac{1}{30} + \frac{1}{45}}\).
\(\frac{1}{36} + \frac{1}{30} + \frac{1}{45} = \frac{5 + 6 + 4}{180} = \frac{1}{12}\), so average speed = 3 × 12 = 36 kmph.
Hence, 36 kmph.
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A person travels along the sides of an equilateral triangular field at speeds of 36 km/h, 30 km/h and 45 km/h. Find his average speed.
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