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Question

A moist air parcel at $24^\circ\text{C}$ has a mixing ratio of $10 \text{ g per kg}$. Its virtual temperature is :

The correct answer is
$\sim 25.81^\circ\text{C}$

Calculating Virtual Temperature

The virtual temperature ($T_v$) accounts for the effect of water vapor on the density of air. It is calculated using the dry-bulb temperature ($T$) and the mixing ratio ($r$). The formula used is:

$T_v = T \left( \frac{1 + \frac{r}{0.622}}{1 + r} \right)$

Where:

  • $T$ is the dry-bulb temperature in Kelvin (K).
  • $r$ is the mixing ratio in kg/kg.

Step-by-Step Calculation

  1. Convert Temperature to Kelvin:

    The given dry-bulb temperature is $T = 24^\circ\text{C}$. Convert this to Kelvin:

    $T (\text{K}) = 24 + 273.15 = 297.15 \text{ K}$

  2. Convert Mixing Ratio to kg/kg:

    The given mixing ratio is $10 \text{ g/kg}$. Convert this to kg/kg:

    $r = 10 \text{ g/kg} = 0.010 \text{ kg/kg}$

  3. Calculate Virtual Temperature ($T_v$):

    Substitute the values into the virtual temperature formula:

    $T_v = 297.15 \text{ K} \left( \frac{1 + \frac{0.010}{0.622}}{1 + 0.010} \right)$

    First, calculate the terms inside the fraction:

    $\frac{0.010}{0.622} \approx 0.016077$

    $1 + 0.016077 \approx 1.016077$

    $1 + 0.010 = 1.010$

    Now, substitute these back into the formula:

    $T_v = 297.15 \text{ K} \left( \frac{1.016077}{1.010} \right)$

    $T_v \approx 297.15 \text{ K} \times 1.0060168$

    $T_v \approx 299.00 \text{ K}$

  4. Convert Virtual Temperature back to Celsius:

    Convert the virtual temperature from Kelvin back to Celsius:

    $T_v (\text{°C}) = 299.00 - 273.15$

    $T_v \approx 25.85^\circ\text{C}$

This calculated value is approximately $25.81^\circ\text{C}$, matching Option A.

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Important Questions from Meteorology

  1. The secondary pollutant in the troposphere is

  2. Inversion that occurs near Earth’s Surface is called :
  3. In an urban area, moist air at 27 °C has a mixing ratio of 50 gm per kg. Its virtual temperature is
  4. The atmospheric condition at a given time is shown in figure given below. If the average wind speed that prevailed was 10 m/s, what will be the ventilation coefficient?

  5. Match the LIST-I with LIST-II
    LIST-I
    Reduction in Ambient temperature with height is Y. Dry and saturated adiabatic lapse rates are Yd and Ys, respectively
    LIST-II
    Stability class
    A. Y < YsI. Absolutely Unstable
    B. Y > YdII. Conditionally Unstable
    C. Y = YdIII. Absolutely Stable
    D. Ys > Y > YdIV. Dry Neutral

    Choose the correct answer from the options given below:
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