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Question

A man goes from point A to point B at a speed of 13 km/h and returns from B to A at a speed of 10 km/h using the same route. The average speed (in km/h) for the whole journey is:

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is
$11\frac{7}{23}$

Average Speed Calculation for Round Trip

The problem requires calculating the average speed for a journey covering the same distance twice, but at different speeds.

Key Concepts

  • Average Speed Formula: When the distance is the same for two parts of a journey, the average speed is the harmonic mean of the two speeds.
  • Formula: Average Speed = \(\frac{2}{\frac{1}{v_1} + \frac{1}{v_2}}\), where \(v_1\) and \(v_2\) are the speeds for the two parts.

Given Information

  • Speed from A to B (\(v_1\)) = 13 km/h
  • Speed from B to A (\(v_2\)) = 10 km/h

Step-by-Step Calculation

  1. Apply the Average Speed Formula: Substitute the given speeds into the formula.

    Average Speed = \(\frac{2}{\frac{1}{13 \, \text{km/h}} + \frac{1}{10 \, \text{km/h}}}\)

  2. Find a Common Denominator for the Speeds in the Denominator: The common denominator for 13 and 10 is \(13 \times 10 = 130\).

    Average Speed = \(\frac{2}{\frac{10}{130} + \frac{13}{130}}\)

    Average Speed = \(\frac{2}{\frac{10 + 13}{130}}\)

    Average Speed = \(\frac{2}{\frac{23}{130}}\)

  3. Simplify the Expression: Divide 2 by the fraction \(\frac{23}{130}\).

    Average Speed = \(2 \times \frac{130}{23}\)

    Average Speed = \(\frac{260}{23}\) km/h

  4. Convert to Mixed Fraction: Divide 260 by 23.

    \(260 \div 23 = 11\) with a remainder of \(7\).

    Therefore, the average speed is \(11\frac{7}{23}\) km/h.

Conclusion

The average speed for the whole journey is \(\frac{260}{23}\) km/h, which is equivalent to \(11\frac{7}{23}\) km/h.

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