Rama walks to her office, 5 km away from home. In the morning, she covers the distance in 1 hour, whereas while returning home in the evening, she takes 15 more minutes to cover the same distance. Find her average speed (in km/h) during the two-way journey.
\(4 rac{4}{9}\)
The correct answer is Option 2 i.e. \(4 rac{4}{9}\).
Time taken in the evening = 1 hour + 15 minutes = 1 + \(15\over60\) = 1 + \(1\over4\) = \(5\over4\) hour
Total distance = 5 + 5 = 10 km
Total time = 1 + \(5\over4\) = \(9\over4\) hours
Average speed = Total distance/Total time
⇒ 10/(9/4) = \(40\over9\) = \(4 rac{4}{9}\)
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