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Question

Two runners, A and B, cover the same distance at the speeds of 15 km/h and 16 km/h, respectively. If A takes 16 min more than B, then the distance (in km) is:

This question was previously asked in
RRB ALP/Technician 2018 CBT 2 Electronics Mechanic Question Paper (23-Jan-2019) (Shift 1)
The correct answer is
64

Distance Calculation: Runners' Problem

This problem requires finding the distance covered by two runners, A and B. We are given their respective speeds and the time difference between them covering the same distance.

  • Runner A's Speed (\(S_A\)): 15 km/h
  • Runner B's Speed (\(S_B\)): 16 km/h
  • Time difference (\(T_A - T_B\)): 16 minutes
  • The distance (\(D\)) is the same for both runners.

Time Difference: Minutes to Hours Conversion

To maintain consistency with the speeds given in kilometers per hour (km/h), the time difference must be converted from minutes to hours.

Time difference = 16 minutes = \( \frac{16}{60} \) hours = \( \frac{4}{15} \) hours.

Distance Equation Formulation

The fundamental relationship between distance, speed, and time is Time = Distance / Speed (\( T = \frac{D}{S} \)). Let \(T_A\) be the time taken by runner A and \(T_B\) be the time taken by runner B.

  • Time for Runner A: \( T_A = \frac{D}{15} \)
  • Time for Runner B: \( T_B = \frac{D}{16} \)

Since Runner A takes 16 minutes (i.e., \( \frac{4}{15} \) hours) longer than Runner B, we can write the equation:

\( T_A - T_B = \frac{4}{15} \)

Substitute the expressions for \( T_A \) and \( T_B \):

\( \frac{D}{15} - \frac{D}{16} = \frac{4}{15} \)

Solving the Distance Equation

To find the distance \(D\), we need to solve the equation. First, find a common denominator for the terms involving \(D\) on the left side.

The least common multiple of 15 and 16 is \( 15 \times 16 = 240 \). Adjust the fractions:

\( \frac{16D}{240} - \frac{15D}{240} = \frac{4}{15} \)

Combine the terms:

\( \frac{16D - 15D}{240} = \frac{4}{15} \)

\( \frac{D}{240} = \frac{4}{15} \)

Isolate \(D\) by multiplying both sides by 240:

\( D = \frac{4}{15} \times 240 \)

Simplify the calculation:

\( D = 4 \times \frac{240}{15} \)

\( D = 4 \times 16 \)

\( D = 64 \)

Final Calculated Distance

The calculated distance covered by both runners is 64 km.

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Similar Questions

  1. A train travels 45 m in 3 s. What is the speed of the train in km/h?
  2. Two runners, A and B, cover the same distance at the speeds of 15 km/h and 16 km/h, respectively. If A takes 16 min more than B, then the distance (in km) is:
  3. A boy goes to school at a speed of 5 km/hr. He returns at a speed of 14 km/hr. He takes a total of 8 hours for both going to school and returning. The distance (in km) between his home and school is:

  4. Two trains of lengths 155 m and 160 m are running at speeds of 74 km/hr and 52 km/hr, respectively, on parallel tracks in opposite directions. In how many seconds will they pass each other?

  5. Raj takes $2 \frac{1}{3}$ hours to complete a certain distance at a speed of 51 km/hr. What time would Kiran take to complete the same distance at a speed of 68km/hr?
  6. An auto A covers a distance in 2 hours at the speed of 42 km/hr. Another auto B covers twice the distance covered by A in 5 hours. What is the speed of auto B (in km/hr)?
  7. Two trains travelling in the same direction at 40 km/h and 22 km/h cross each other completely in 1 minute. If the length of the first train is 125 m, what is the length of the second train?
  8. A 280 m long train running at a speed of 72 km/hr passes a platform in 30 seconds. Find the length of the platform (in m).

  9. Vijay rides a bicycle 10 m from home to his tuition, then 5 m to a shop. He travels back home the same way, covering the same distance. What is his total path length?

  10. Rinku riding his car covers 136 metres in 17 seconds. What is his speed (in km/hr)?


Important Questions from Speed Time and Distance

  1. A train travelling at a speed of 72 km/hr crosses a post in 20 seconds. If it crosses another train travelling at a speed of 54 km/hr in the same direction in 1 minute 45 seconds, then the difference in length between the two trains is

  2. Rajiv's boat can travel along the current at the 8 km/hour and against the current at the rate 6 km/hour. Find the time taken by the boat to sail 28 km in still water.

  3. Two trains running in opposite directions cross a man standing on the platform in 25 seconds and 32 seconds respectively and they cross each other in 30 seconds. The ratio of their speed is:

  4. A worker covers a distance of 81 km in 11 hours. He travels partly on foot at 4.5 km/h and partly on bicycle at 15 km/h. What is the distance covered on the cycle?

  5. A car travels from a place X to place Y at an average speed of v km/hr from y to X at an average speed of 2v km/hr, again from X to y at an average speed of 3v km/hr and again from y to x at an average speed of 4v km/hr. Then the average speed of the car for the entire journey

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